AMS104W Panasonic Electric Works, AMS104W Datasheet - Page 2

SENSOR LIGHT NAPICA 6V SMD

AMS104W

Manufacturer Part Number
AMS104W
Description
SENSOR LIGHT NAPICA 6V SMD
Manufacturer
Panasonic Electric Works
Datasheet

Specifications of AMS104W

Wavelength
580nm
Output Type
Analog
Package / Case
Surface Mount
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Other names
255-2654-2
3. Electrical characteristics (Ambient temperature: 25°C 77°F)
*
*
*
REFERENCE DATA
1. Power dissipation vs. ambient temperature
characteristics
4. Photocurrent vs. brightness characteristics
Light source: Fluorescent lamp, CIE standard “A”
Reverse voltage: 5V, Ambient temperature: 25°C
Peak sensitivity wavelength
Photocurrent 1
Photocurrent 2
Photocurrent 3
Dark current
Switching time
1
2
3
Fluorescent lamp is used as light source.
CIE standard illuminant ‘A’ is used as light source.
Measuring method for switching time.
White LED
10000
1000
100
50
40
30
20
10
10
I
0
F
1
0
1
Fluorescent lamp
CIE standard “A”
20
10
Ambient temperature, °C
40
AMS104
R
Item
Rise time
Fall time
L
Brightness, lx
100
60
V
0
1000
8085
Minimum
Typical
Maximum
Minimum
Typical
Maximum
Typical
Maximum
Typical
Typical
5.0V
10000
100
77°F
I
V
F
0
2. Relative sensitivity vs. wavelength
characteristics
Ambient temperature: 25°C
5. Relative photocurrent vs. ambient
temperature characteristics
Light source: Fluorescent lamp, Brightness: 100 lx
Reverse voltage: 5V
Symbol
λp
I
I
I
I
t
t
L1
L2
L3
2.5V
D
r
f
tr
1.0
0.8
0.6
0.4
0.2
1.4
1.2
1.0
0.8
0.6
0
–40
400
500
–20
11/2004
600
0
Ambient temperature, °C
700
Wavelength, nm
20
77°F
800 900 1000 1100
40
Human spectral
NaPiCa spectral
AMS104
16.9 µA
580 nm
182 µA
260 µA
338 µA
500 µA
8.5 ms
8.5 ms
9.1 µA
0.3 µA
13 µA
tf
60
90%
10%
80
100
3. Dark current vs. ambient temperature
characteristics
Reverse voltage: 5V
6. Relative photocurrent vs. reverse voltage
characteristics
Light source: Fluorescent lamp, Brightness: 100 lx
Ambient temperature: 25°C
V
V
V
V
V
Light Sensor (AMS1)
R
R
R
R
R
0.001
0.01
1.2
1.0
0.8
0.6
0.4
0.2
= 5 V E
= 5 V E
= 5 V E
= 5 V
= 2.5 V, V
0.1
10
0
1
20
0
1
V
V
V
= 5 lx*
= 100 lx*
= 100 lx*
O
40
2
= 2.5 V R
Ambient temperature, °C
Condition
3
Reverse voltage, V
1
77°F
1
2
60
4
L
= 5 kΩ
5
80
6
7
100
8
5

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