S-814A50AMC-BDOT2G Seiko Instruments, S-814A50AMC-BDOT2G Datasheet - Page 24

• Manufacturer Part Number: S-814A50AMC-BDOT2G
• Description: IC REG LDO 180MA 5.0V SOT23-5
• Manufacturer: Seiko Instruments

Specifications of S-814A50AMC-BDOT2G

• Regulator Topology: Positive Fixed
• Voltage - Output: 5V
• Voltage - Input: Up to 10V
• Voltage - Dropout (typical): 0.17V @ 60mA
• Number Of Regulators: 1
• Current - Output: 180mA (Min)
• Operating Temperature: -40°C ~ 85°C
• Mounting Type: Surface Mount
• Package / Case: SOT-23-5, SC-74A, SOT-25
• Number Of Outputs: 1
• Polarity: Positive
• Input Voltage Max: 12 V
• Output Voltage: 5 V
• Output Type: Fixed
• Dropout Voltage (max): 0.87 V
• Output Current: 70 mA
• Line Regulation: 0.2 %/V
• Load Regulation: 50 mV
• Voltage Regulation Accuracy: 2 %
• Maximum Power Dissipation: 250 mW
• Maximum Operating Temperature: + 85 C
• Mounting Style: SMD/SMT
• Minimum Operating Temperature: - 40 C
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Current - Limit (min): -
• Lead Free Status / Rohs Status: Lead free / RoHS Compliant

24
LOW DROPOUT CMOS VOLTAGE REGULATOR
S-814 Series
1-4. At load fluctuation
Output voltage (V
Load current dependencies of overshoot
Remark ΔI
V
DD
dependencies of overshoot
30 mA
1.0
0.8
0.6
0.4
0.2
10 μA
0.8
0.6
0.4
0.2
current fluctuation. Smaller current at load
current fluctuation is fixed to 10 µA.
i.e. ΔI
3 V
0
1.E−03
1
0
0
OUT
V
V
V
fluctuation from 10 mA to 10 µA.
IN
OUT
IN
V
shows larger load current at load
=V
OUT
=V
OUT
OUT
I
OUT
OUT(S)
DD
2
=1.E−02 [A] means load current
=2 V
C
L
, I
) – Time (t)
=1 μF
1.E−02
OUT
+1 V, C
=30 mA→10 μA, C
4
I
t [20 μs/div]
OUT
ΔI
V
3 V
C
3 V
DD
OUT
L
=10 μA→30 mA, V
L
=4.7 μF
=1 μF
[V]
[A]
1.E−01
5 V
6
V
OUT
=2 V
8
5 V
Seiko Instruments Inc.
L
=1 μF
1.E+00
IN
=4 V
10
C
Temperature dependencies of overshoot
L
dependencies of overshoot
V
30 mA
IN
10 μA
V
1.0
0.8
0.6
0.4
0.2
=V
IN
3 V
0
=V
−50
1.0
0.8
0.6
0.4
0.2
0
OUT(S)
OUT(s)
0.1
V
OUT
V
+1 V, I
OUT
I
+1 V, I
V
OUT
=2 V
5 V
OUT
3 V
=2
OUT
C
V
OUT
L
0
=4.7 μF
1
=30 mA→10 μA, C
=30 mA→10 μA
t [20 ms/div]
C
I
Ta [°C]
OUT
L
3 V
[μF]
=30 mA→10 μA, V
C
10
L
50
=1 μF
Rev.3.0
5 V
L
=1 μF
100
IN
=4 V
100
_00