CSTCR6M00G53-R0 Murata, CSTCR6M00G53-R0 Datasheet - Page 10
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CSTCR6M00G53-R0
Manufacturer Part Number
CSTCR6M00G53-R0
Description
Resonators 6.00MHz 0.5%
Manufacturer
Murata
Series
CSTCR-Gr
Datasheets
1.CSTCW20M0X53-R0.pdf
(32 pages)
2.CSTCE20M0V53-R0.pdf
(1 pages)
3.CSTCC2M00G56-R0.pdf
(21 pages)
4.CSTCR6M00G53-R0.pdf
(8 pages)
Specifications of CSTCR6M00G53-R0
Tolerance
0.5 %
Termination Style
SMD/SMT
Operating Temperature Range
- 20 C to + 80 C
Dimensions
2 mm W x 4.5 mm L x 1.5 mm H
Frequency Stability
0.2 %
Frequency
6 MHz
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
CSTCR6M00G53-R0
Manufacturer:
MURATA
Quantity:
9 000
2
8
2
Note
(Note 1)
The relationship between the size of the resonator
and the resonant frequency is described as follows.
For example, the frequency doubles if the thickness
doubles, when thickness vibration is used.
The following relationship is obtained when the
length of the resonators is ℓ, the resonance
frequency is Fr, the speed of sound waves travelling
through piezoelectric ceramics, and the wavelength
is λ.
As seen in the above formula, the frequency
constant determines the size of the resonator.
• Please read rating and
• This catalog has only typical specifications because there is no space for detailed specifications. Therefore, please review our product specifications or consult the approval sheet for product specifications before ordering.
Principles of CERALOCK
Notes
Fr . ℓ = Const.
(frequency constant, Fr . t for the thickness)
λ = 2 ℓ
C = Fr . λ = 2Fr . ℓ
CAUTION (for storage, operating, rating, soldering, mounting and handling) in this catalog to prevent smoking and/or burning, etc.
(Min.Amplitude) (Max.Amplitude)
Fig. Ⅰ
Amplitude
Range of
Standing
Wave
®
(Note 2)
In Fig. 2-3, when resistance R
simplification, the impedance Z (ω) between two
terminals is expressed by the following formula.
Therefore from ω =2πF,
Fr = ωr/2π =
Fa = ωa/2π =
Z (ω) =
When ω =
When ω =
=
j ( ωL
1 +
jωC
jωC
1
1
2π
2π
0
0
C
L
C
C
1
1 –
1
( jωL
+ ( jωL
0
0
1
C
C
1
L
1
1
ωC
C
L
– ω
1
0
1
= ωr, Z (ωr) =0
C
L
1
1
C
1
1
Fig. Ⅱ
/(C
1
+
1
1
2
1
1
L
C
jωC
+
)
C
0+
0
1
1
/(C
jωC
0
C
L
C
1
1
1
1
1
)
0
1
+C
)
1
is omitted for
= ωa, Z (ωa) = ∞
)
1
)
= Fr
1+
C
C
1
0
P17E.pdf
SEP.16,
2011