2N6284 ON Semiconductor, 2N6284 Datasheet - Page 3

Darlington Transistors 20A 100V Bipolar

2N6284

Manufacturer Part Number
2N6284
Description
Darlington Transistors 20A 100V Bipolar
Manufacturer
ON Semiconductor
Datasheet

Specifications of 2N6284

Configuration
Single
Transistor Polarity
NPN
Mounting Style
Through Hole
Package / Case
TO-204-2 (TO-3)
Collector- Emitter Voltage Vceo Max
100 V
Emitter- Base Voltage Vebo
5 V
Collector- Base Voltage Vcbo
100 V
Maximum Dc Collector Current
20 A
Maximum Collector Cut-off Current
500 uA
Power Dissipation
160 W
Maximum Operating Temperature
+ 200 C
Continuous Collector Current
20 A
Dc Collector/base Gain Hfe Min
100, 750
Minimum Operating Temperature
- 65 C
Lead Free Status / RoHS Status
Lead free / RoHS Compliant

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
2N6284
Manufacturer:
STM
Quantity:
373
Part Number:
2N6284
Manufacturer:
ST
0
Part Number:
2N6284G
Manufacturer:
ON Semiconductor
Quantity:
145
0.07
0.05
0.03
0.02
0.01
1.0
0.7
0.5
0.3
0.2
0.1
0.01
D = 0.5
0.2
0.1
0.05
0.02
0.02 0.03 0.05
SINGLE PULSE
0.01
APPROX
7.0
5.0
3.0
2.0
1.0
0.7
0.5
0.3
0.2
0.1
APPROX
- 12 V
10
+ 8.0 V
0.1
R
V
0.2
V
B
1
2
DUTY CYCLE = 1.0%
0
& R
V
I
I
T
C
B1
CC
J
/I
= 25°C
C
B
t
= I
0.3
D
r
0.2
, t
= 30 Vdc
VARIED TO OBTAIN DESIRED CURRENT LEVELS
= 250
Figure 2. Switching Times Test Circuit
1
B2
1N5825 USED ABOVE I
MSD6100 USED BELOW I
f
MUST BE FAST RECOVERY TYPE e.g.,
25 ms
v 10 ns
t
s
0.3
0.5
Figure 3. Switching Times
I
0.7
C
0.5
, COLLECTOR CURRENT (AMP)
1.0
Figure 4. Thermal Response
FOR t
AND V
FOR NPN TEST CIRCUIT REVERSE ALL POLARITIES
http://onsemi.com
1.0
t, TIME OR PULSE WIDTH (ms)
51
B
d
t
f
2
2.0
AND t
[ 100 mA
R
B
= 0
D
B
[ 100 mA
2.0
+ 4.0 V
1
2N6284 (NPN)
3
2N6287 (PNP)
t
r
d
3.0
, D
@ V
3.0
1
IS DISCONNECTED
t
r
BE(off)
5.0
[ 8.0 k
5.0
R
R
D CURVES APPLY FOR POWER
PULSE TRAIN SHOWN
READ TIME AT t
T
J(pk)
qJC
qJC
= 0 V
7.0
(t) = r(t) R
= 1.09°C/W MAX
- T
10
TUT
10
C
[ 50
= P
(pk)
qJC
- 30 V
1
20
V
20
R
CC
qJC
R
C
30
(t)
SCOPE
50
P
(pk)
100
DUTY CYCLE, D = t
t
1
200
t
2
300
1
500
/t
2
1000

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