AD835AR-REEL Analog Devices Inc, AD835AR-REEL Datasheet - Page 12

• Manufacturer Part Number: AD835AR-REEL
• Description: IC,Analog Multiplier,BIPOLAR,SOP,8PIN,PLASTIC
• Manufacturer: Analog Devices Inc

Specifications of AD835AR-REEL

• Rohs Status: RoHS non-compliant
• Function: Analog Multiplier
• Number Of Bits/stages: 4-Quadrant
• Package / Case: 8-SOIC (3.9mm Width)

AD835
SQUARING AND FREQUENCY DOUBLING
Amplitude domain squaring of an input signal, E, is achieved
simply by connecting the X and Y inputs in parallel to produce
an output of E
output in this case is always positive. The output polarity can be
reversed by interchanging either the X or Y inputs.
When the input is a sine wave E sin ωt, a signal squarer behaves
as a frequency doubler because
While useful, Equation 6 shows a dc term at the output, which
varies strongly with the amplitude of the input, E.
Figure 24 shows a frequency doubler that overcomes this
limitation and provides a relatively constant output over a
moderately wide frequency range, determined by the time
constant R1C1. The voltage applied to the X and Y inputs is
exactly in quadrature at a frequency f = ½πC1R1, and their
amplitudes are equal. At higher frequencies, the X input becomes
smaller while the Y input increases in amplitude; the opposite
happens at lower frequencies. The result is a double frequency
output centered on ground whose amplitude of 1 V for a 1 V
input varies by only 0.5% over a frequency range of ±10%.
Because there is no squared dc component at the output, sudden
changes in the input amplitude do not cause a bounce in the dc level.
(
E
sin
U
ωt
)
2
2
/U. The input can have either polarity, but the
=
2
E
U
2
(
1
−
cos
2
ωt
)
Rev. D | Page 12 of 16
(6)
This circuit is based on the identity
At ω
attenuated by √2, while the Y input lags the input signal by 45°
and is also attenuated by √2. Because the X and Y inputs are 90°
out of phase, the response of the circuit is
which has no dc component, R2 and R3 are included to restore
the output to 1 V for an input amplitude of 1 V (the same gain
adjustment as previously mentioned). Because the voltage across
the capacitor (C1) decreases with frequency, while that across
the resistor (R1) increases, the amplitude of the output varies
only slightly with frequency. In fact, it is only 0.5% below its full
value (at its center frequency ω
this frequency.
W
=
O
cos
U
1
= 1/C1R1, the X input leads the input signal by 45° (and is
V
G
θ
Figure 24. Broadband Zero-Bounce Frequency Doubler
E
2
sin
(
sin
θ
C1
R1
=
ω
t
1
2
X1
Y1
8
1
−
sin
45
2
°
θ
X2
)
Y2
AD835
2
7
E
2
(
+5V
–5V
sin
VP
VN
O
6
3
= 1/C1R1) at 90% and 110% of
ω
t
+
W
Z
4
5
45
°
)
=
R2
97.6Ω
R3
301Ω
2
E
U
2
(
sin
VOLTAGE
OUTPUT
2
ω
t
)
(7)
(8)