ADA4505-2ARMZ-RL Analog Devices Inc, ADA4505-2ARMZ-RL Datasheet - Page 8

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ADA4505-2ARMZ-RL

Manufacturer Part Number
ADA4505-2ARMZ-RL
Description
DUAL LV 10uA CMOS OPAmp AD8506derivative
Manufacturer
Analog Devices Inc
Datasheet

Specifications of ADA4505-2ARMZ-RL

Design Resources
Precision Pulse Oximeter LED Current Sinks Using ADA4505-2, ADR1581, and ADG1636 (CN0125)
Amplifier Type
Voltage Feedback
Number Of Circuits
2
Output Type
Rail-to-Rail
Slew Rate
0.006 V/µs
Gain Bandwidth Product
50kHz
Current - Input Bias
0.5pA
Voltage - Input Offset
500µV
Current - Supply
7µA
Current - Output / Channel
40mA
Voltage - Supply, Single/dual (±)
1.8 V ~ 5 V, ±0.9 V ~ 2.5 V
Operating Temperature
-40°C ~ 125°C
Mounting Type
Surface Mount
Package / Case
8-MSOP, Micro8™, 8-uMAX, 8-uSOP,
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
-3db Bandwidth
-
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Other names
ADA4505-2ARMZ-RLTR

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
ADA4505-2ARMZ-RL
Manufacturer:
AD
Quantity:
11 690
ADA4505-2
T
Figure 14. Output Voltage (V
A
= 25°C, unless otherwise noted.
1.800
1.795
1.790
1.785
1.780
1.775
Figure 15. Output Voltage (V
Figure 16. Output Voltage (V
0.01
25
20
15
10
10k
100
0.1
5
0
1k
10
–40
0.001
1
–40
V
V
SY
SY
–25
V
–25
SY
= 1.8V
= 1.8V
= 1.8V
–10
–10
0.01
5
5
OL
) to Supply Rail vs. Load Current and Temperature
TEMPERATURE (°C)
20
LOAD CURRENT (mA)
TEMPERATURE (°C)
20
0.1
R
R
OH
R
OL
35
L
R
L
35
L
) to Supply Rail vs. Temperature
L
) to Supply Rail vs. Temperature
= 100kΩ
= 10kΩ
= 100kΩ
= 10kΩ
50
50
1
65
65
80
80
95
10
95
110
–40°C
+25°C
+85°C
+125°C
110
125
100
125
Rev. 0 | Page 8 of 20
Figure 17. Output Voltage (V
5.000
4.995
4.990
4.985
4.980
4.975
4.970
Figure 18. Output Voltage (V
Figure 19. Output Voltage (V
0.01
25
20
15
10
10k
100
0.1
5
0
–40
1k
10
0.001
1
–40
V
V
SY
SY
–25
V
–25
= 5V
SY
= 5V
= 5V
–10
–10
0.01
5
5
OL
) to Supply Rail vs. Load Current and Temperature
TEMPERATURE (°C)
20
LOAD CURRENT (mA)
TEMPERATURE (°C)
20
0.1
R
R
R
R
OH
L
L
OL
35
L
L
= 100kΩ
35
= 100kΩ
) to Supply Rail vs. Temperature
= 10kΩ
) to Supply Rail vs. Temperature
= 10kΩ
50
50
1
65
65
80
80
95
10
95
110
–40°C
+25°C
+85°C
+125°C
110
125
125
100

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