30CPQ060PBF Vishay, 30CPQ060PBF Datasheet - Page 3

• Manufacturer Part Number: 30CPQ060PBF
• Description: DIODE SCHOTTKY 60V 15A TO247AC
• Manufacturer: Vishay

Specifications of 30CPQ060PBF

• Voltage - Forward (vf) (max) @ If: 600mV @ 15A
• Current - Reverse Leakage @ Vr: 800µA @ 60V
• Current - Average Rectified (io) (per Diode): 15A
• Voltage - Dc Reverse (vr) (max): 60V
• Diode Type: Schottky
• Speed: Fast Recovery =< 500ns, > 200mA (Io)
• Diode Configuration: 1 Pair Common Cathode
• Mounting Type: Through Hole, Radial
• Package / Case: TO-247-3 (Straight Leads), TO-247AC
• Product: Schottky Rectifiers
• Peak Reverse Voltage: 60 V
• Forward Continuous Current: 30 A
• Max Surge Current: 1020 A
• Configuration: Dual Common Cathode
• Forward Voltage Drop: 0.8 V
• Maximum Reverse Leakage Current: 800 uA
• Operating Temperature Range: - 55 C to + 150 C
• Mounting Style: Through Hole
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Reverse Recovery Time (trr): -
• Lead Free Status / Rohs Status: Lead free / RoHS Compliant
• Other names: *30CPQ060PBF; VS-30CPQ060PBF; VS-30CPQ060PBF; VS30CPQ060PBF; VS30CPQ060PBF

Document Number: 93300
Revision: 22-Aug-08
Fig. 1 - Maximum Forward Voltage Drop Characteristics
0
0.001
0.2
0.01
0.1
10
0.00001
V
1
FM
0.4
- Forward Voltage Drop (V)
0.6
(Per Leg)
0.8
Fig. 4 - Maximum Thermal Impedance Z
0.0001
Fig. 3 - Typical Junction Capacitance vs. Reverse Voltage (Per Leg)
1.0
T
T
T
(thermal resistance)
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J
J
J
= 150 °C
= 125 °C
= 25 °C
1.2
Single pulse
Schottky Rectifier, 2 x 15 A
1.4
0.001
0
1.6
t
1
1.8
- Rectangular Pulse Duration (s)
10
V
R
- Reverse Voltage (V)
0.01
T
20
J
30CPQ035/30CPQ040/30CPQ045
= 25 °C
thJC
D = 0.50
D = 0.33
D = 0.25
D = 0.17
D = 0.08
30
Characteristics (Per Leg)
0.1
40
0
Fig. 2 - Typical Values of Reverse Current vs.
Vishay High Power Products
Notes:
1. Duty factor D = t
2. Peak T
5
50
1
T
10
Reverse Voltage (Per Leg)
V
J
R
= 50 °C
J
T
T
- Reverse Voltage (V)
J
= P
T
15
J
J
= 25 °C
= 100 °C
= 75 °C
P
DM
T
DM
J
20
= 125 °C
x Z
10
T
1
/t
J
t
1
thJC
2
= 150 °C
t
2
25
+ T
C
30
35
100
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40
45
3