MBR2045CT-1PBF Vishay, MBR2045CT-1PBF Datasheet - Page 3

• Manufacturer Part Number: MBR2045CT-1PBF
• Description: DIODE SCHOTTKY 45V 10A TO262
• Manufacturer: Vishay

Specifications of MBR2045CT-1PBF

• Diode Configuration: 1 Pair Common Cathode
• Diode Type: Schottky
• Voltage - Forward (vf) (max) @ If: 840mV @ 20A
• Current - Reverse Leakage @ Vr: 100µA @ 45V
• Current - Average Rectified (io) (per Diode): 10A
• Voltage - Dc Reverse (vr) (max): 45V
• Speed: Fast Recovery =< 500ns, > 200mA (Io)
• Mounting Type: Through Hole, Radial
• Package / Case: I²Pak, TO-262 (3 straight leads + tab)
• Product: Schottky Diodes
• Peak Reverse Voltage: 45 V
• Forward Continuous Current: 20 A
• Max Surge Current: 1060 A
• Configuration: Dual Common Cathode
• Forward Voltage Drop: 0.84 V
• Maximum Reverse Leakage Current: 100 uA
• Operating Temperature Range: - 65 C to + 150 C
• Mounting Style: Through Hole
• Repetitive Reverse Voltage Vrrm Max: 45V
• Forward Current If(av): 20A
• Forward Voltage Vf Max: 840mV
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Reverse Recovery Time (trr): -
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant, Lead free / RoHS Compliant
• Other names: *MBR2045CT-1PBF

www.irf.com
1 0 0
10
1
0 .2
Fig. 1 - Max. Forward Voltage Drop Characteristics
0.0 1
0 .4
0 .1
0.0 00 0 1
1 0
1
Forw a rd V olta ge D rop - V
0.6
D = 0 .7 5
D = 0 .5 0
D = 0 .3 3
D = 0 .2 5
D = 0 .2 0
Fig. 4 - Max. Thermal Impedance Z
0.8
(Per Leg)
0.0 00 1
(The rm a l R e sista n c e)
1
Sin g le Pu lse
t , R e cta n g ula r P u lse D ura tio n (Seco nd s)
1 .2
1
T = 15 0 C
T = 12 5 C
T = 2 5 C
FM
0 .0 0 1
J
J
J
1 .4
(V )
1.6
MBR20...CT, MBRB20...CT, MBR20...CT-1
1.8
0.0 1
thJC
Characteristics (Per Leg)
0 .00 0 1
0.0 01
1 000
Notes:
1. D uty fa ctor D = t / t
2. Pea k T = P
0 .01
0.1
10 0
100
0.1
1 0
1 0
1
Fig. 2 - Typical Values Of Reverse Current
0
0
Fig. 3 - Typical Junction Capacitance
J
T = 15 0 C
J
P
Vs. Reverse Voltage (Per Leg)
Vs. Reverse Voltage (Per Leg)
D M
2 0
20
D M
Bulletin PD-2.321 rev. I 08/02
125 C
100 C
Reverse V olta ge - V
Reverse V oltag e - V
75 C
50 C
25 C
1 t
1
x Z
2 t
thJC
1
4 0
4 0
T = 25 C
+ T
J
2
C
10
60
6 0
R
R
(V )
(V )
80
8 0
1 0 0
10 0
3