12CTQ045PBF Vishay, 12CTQ045PBF Datasheet - Page 3

• Manufacturer Part Number: 12CTQ045PBF
• Description: DIODE SCHOTTKY 45V 6A TO220AB
• Manufacturer: Vishay

Specifications of 12CTQ045PBF

• Voltage - Forward (vf) (max) @ If: 600mV @ 6A
• Current - Reverse Leakage @ Vr: 800µA @ 45V
• Current - Average Rectified (io) (per Diode): 6A
• Voltage - Dc Reverse (vr) (max): 45V
• Diode Type: Schottky
• Speed: Fast Recovery =< 500ns, > 200mA (Io)
• Diode Configuration: 1 Pair Common Cathode
• Mounting Type: Through Hole
• Package / Case: TO-220-3 (Straight Leads)
• Product: Schottky Diodes
• Peak Reverse Voltage: 45 V
• Forward Continuous Current: 12 A
• Max Surge Current: 690 A
• Configuration: Dual Common Cathode
• Forward Voltage Drop: 0.73 V
• Maximum Reverse Leakage Current: 800 uA
• Operating Temperature Range: - 55 C to + 175 C
• Mounting Style: Through Hole
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Reverse Recovery Time (trr): -
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant, Lead free / RoHS Compliant
• Other names: *12CTQ045PBF; VS-12CTQ045PBF; VS-12CTQ045PBF; VS12CTQ045PBF; VS12CTQ045PBF

Document Number: 94130
Revision: 13-Aug-08
Fig. 1 - Maximum Forward Voltage Drop Characteristics
0.001
0.2
0.01
0.1
10
0.00001
1
0.4
V
D = 0.75
D = 0.50
D = 0.33
D = 0.25
D = 0.20
FM
- Forward Voltage Drop (V)
0.6
0.0001
(Per Leg)
0.8
Fig. 4 - Maximum Thermal Impedance Z
(thermal resistance)
Fig. 3 - Typical Junction Capacitance vs. Reverse Voltage (Per Leg)
T
T
T
J
J
J
1.0
Single pulse
= 175 °C
= 125 °C
= 25 °C
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1000
100
1.2
0.001
0
Schottky Rectifier, 2 x 6 A
1.4
t
1
- Rectangular Pulse Duration (s)
10
1.6
V
R
0.01
- Reverse Voltage (V)
20
T
30
J
thJC
= 25 °C
0.1
Characteristics (Per Leg)
40
0.0001
0.001
0.01
100
0.1
10
1
Notes:
1. Duty factor D = t
2. Peak T
0
Fig. 2 - Typical Values of Reverse Current vs.
Vishay High Power Products
50
1
T
5
J
= 25 °C
J
V
= P
T
10
12CTQ...PbF Series
Reverse Voltage (Per Leg)
J
R
= 50 °C
DM
- Reverse Voltage (V)
P
DM
15
x Z
T
1
10
J
/t
t
= 75 °C
1
thJC
2
t
2
T
20
.
J
+ T
= 100 °C
T
C
25
J
= 125 °C
T
J
.
30
= 150 °C
100
T
J
35
= 175 °C
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40
45
3