63CTQ100PBF Vishay, 63CTQ100PBF Datasheet - Page 3

DIODE SCHOTTKY 100V 30A TO220AB

63CTQ100PBF

Manufacturer Part Number
63CTQ100PBF
Description
DIODE SCHOTTKY 100V 30A TO220AB
Manufacturer
Vishay
Datasheet

Specifications of 63CTQ100PBF

Voltage - Forward (vf) (max) @ If
820mV @ 30A
Current - Reverse Leakage @ Vr
300µA @ 100V
Current - Average Rectified (io) (per Diode)
30A
Voltage - Dc Reverse (vr) (max)
100V
Diode Type
Schottky
Speed
Fast Recovery =< 500ns, > 200mA (Io)
Diode Configuration
1 Pair Common Cathode
Mounting Type
Through Hole
Package / Case
TO-220-3 (Straight Leads)
Product
Schottky Diodes
Peak Reverse Voltage
100 V
Forward Continuous Current
30 A
Max Surge Current
1500 A
Configuration
Dual Common Cathode
Forward Voltage Drop
1 V @ 60 A
Maximum Reverse Leakage Current
300 uA
Operating Temperature Range
- 65 C to + 175 C
Mounting Style
Through Hole
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Reverse Recovery Time (trr)
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant
Other names
*63CTQ100PBF
VS-63CTQ100PBF
VS-63CTQ100PBF
VS63CTQ100PBF
VS63CTQ100PBF
Document Number: 93380
Revision: 21-Aug-08
Fig. 1 - Maximum Forward Voltage Drop Characteristics
1000
100
10
1
0
0.001
0.2
0.01
0.1
10
0.00001
V
1
FM
0.4
- Forward Voltage Drop (V)
0.6
0.8
(thermal resistance)
Single pulse
0.0001
1.0
For technical questions, contact: diodes-tech@vishay.com
1.2
Fig. 4 - Maximum Thermal Impedance Z
T
T
T
J
J
J
Fig. 3 - Typical Junction Capacitance vs. Reverse Voltage
= 175 °C
= 125 °C
= 25 °C
1000
Schottky Rectifier, 2 x 30 A
1.4
100
0
1.6
0.001
t
1
1.8
- Rectangular Pulse Duration (s)
20
V
R
- Reverse Voltage (V)
D = 0.75
D = 0.50
D = 0.33
D = 0.25
D = 0.20
40
0.01
T
J
60
= 25 °C
0.0001
thJC
0.001
1000
0.01
100
0.1
10
80
Characteristics
1
0
Fig. 2 - Typical Values of Reverse Current vs.
0.1
Vishay High Power Products
100
20
Notes:
1. Duty factor D = t
2. Peak T
V
T
R
J
- Reverse Voltage (V)
= 175 °C
Reverse Voltage
T
40
J
J
P
= P
= 125 °C
1
DM
DM
T
t
1
J
x Z
t
= 75 °C
2
1
60
/t
T
T
thJC
2
J
J
= 50 °C
63CTQ100
= 25 °C
T
T
+ T
J
J
= 100 °C
= 150 °C
C
80
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10
100
3

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