MBR2045CT Vishay, MBR2045CT Datasheet - Page 3

• Manufacturer Part Number: MBR2045CT
• Description: DIODE SCHOTTKY 45V 10A TO-220AB
• Manufacturer: Vishay

Specifications of MBR2045CT

• Voltage - Forward (vf) (max) @ If: 570mV @ 10A
• Current - Reverse Leakage @ Vr: 100µA @ 45V
• Current - Average Rectified (io) (per Diode): 10A
• Voltage - Dc Reverse (vr) (max): 45V
• Diode Type: Schottky
• Speed: Fast Recovery =< 500ns, > 200mA (Io)
• Diode Configuration: 1 Pair Common Cathode
• Mounting Type: Through Hole
• Package / Case: TO-220-3 (Straight Leads)
• Product: Schottky Diodes
• Peak Reverse Voltage: 45 V
• Forward Continuous Current: 20 A
• Max Surge Current: 1060 A
• Configuration: Dual Common Cathode
• Forward Voltage Drop: 0.84 V
• Maximum Reverse Leakage Current: 100 uA
• Operating Temperature Range: - 65 C to + 150 C
• Mounting Style: Through Hole
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant
• Reverse Recovery Time (trr): -
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant, Lead free / RoHS Compliant
• Other names: *MBR2045CT; MBR2045CTIR; VS-MBR2045CT; VS-MBR2045CTIR; VS-MBR2045CTIR; VSMBR2045CT; VSMBR2045CTIR

Document Number: 93443
Revision: 22-Aug-08
Fig. 1 - Maximum Forward Voltage Drop Characteristics
100
10
1
0.2
0.01
0.4
0.1
10
0.00001
V
1
FM
0.6
- Forward Voltage Drop (V)
0.8
(Per Leg)
(thermal resistance)
0.0001
1.0
Single pulse
Fig. 4 - Maximum Thermal Impedance Z
Fig. 3 - Typical Junction Capacitance vs. Reverse Voltage (Per Leg)
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1.2
T
T
T
J
J
J
= 150 °C
= 125 °C
= 25 °C
1.4
Schottky Rectifier, 2 x 10 A
1000
100
0.001
1.6
0
t
1
1.8
- Rectangular Pulse Duration (s)
10
V
R
- Reverse Voltage (V)
0.01
20
D = 0.75
D = 0.50
D = 0.33
D = 0.25
D = 0.20
T
J
= 25 °C
thJC
30
0.1
Characteristics (Per Leg)
0.0001
0.001
0.01
100
0.1
10
40
1
0
Fig. 2 - Typical Values of Reverse Current vs.
Vishay High Power Products
5
50
1
Notes:
1. Duty factor D = t
2. Peak T
10
Reverse Voltage (Per Leg)
V
R
MBR20..CT Series
- Reverse Voltage (V)
15
T
J
= 150 °C
J
P
= P
DM
20
T
10
J
DM
= 125 °C
t
1
T
x Z
J
25
t
2
T
1
= 75 °C
/t
J
thJC
2
T
= 100 °C
J
T
30
= 50 °C
J
+ T
= 25 °C
C
35
100
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40
45
3