40L15CT Vishay, 40L15CT Datasheet - Page 3

• Manufacturer Part Number: 40L15CT
• Description: DIODE SCHOTTKY 15V 20A TO-220AB
• Manufacturer: Vishay

Specifications of 40L15CT

• Voltage - Forward (vf) (max) @ If: 410mV @ 19A
• Current - Reverse Leakage @ Vr: 10mA @ 15V
• Current - Average Rectified (io) (per Diode): 20A
• Voltage - Dc Reverse (vr) (max): 15V
• Diode Type: Schottky
• Speed: Fast Recovery =< 500ns, > 200mA (Io)
• Diode Configuration: 1 Pair Common Cathode
• Mounting Type: Through Hole
• Package / Case: TO-220-3 (Straight Leads)
• Product: Schottky Rectifiers
• Peak Reverse Voltage: 15 V
• Forward Continuous Current: 20 A
• Max Surge Current: 700 A
• Configuration: Dual Common Cathode
• Forward Voltage Drop: 0.52 V at 40 A
• Maximum Reverse Leakage Current: 10 mA
• Operating Temperature Range: - 55 C to + 125 C
• Mounting Style: Through Hole
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant
• Reverse Recovery Time (trr): -
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant, Lead free / RoHS Compliant
• Other names: *40L15CT; VS-40L15CT; VS-40L15CT; VS40L15CT; VS40L15CT

Document Number: 93342
Revision: 22-Aug-08
Fig. 1 - Maximum Forward Voltage Drop Characteristics
1000
100
10
1
0
0.01
0.2
0.1
10
0.00001
V
1
FM
0.4
- Forward Voltage Drop (V)
0.6
(thermal resistance)
(Per Leg)
0.0001
Single pulse
0.8
Fig. 4 - Maximum Thermal Impedance Z
Fig. 3 - Typical Junction Capacitance vs. Reverse Voltage (Per Leg)
For technical questions, contact: [e-mail]
1.0
T
T
T
J
J
J
= 125 °C
= 75 °C
= 25 °C
10 000
1.2
1000
Schottky Rectifier, 2 x 20 A
100
0.001
1.4
0
t
1
1.6
- Rectangular Pulse Duration (s)
V
5
R
- Reverse Voltage (V)
0.01
D = 0.75
D = 0.50
D = 0.33
D = 0.25
D = 0.20
T
J
10
= 25 °C
thJC
0.1
Characteristics (Per Leg)
1000
15
100
0.1
10
1
Fig. 2 - Typical Values of Reverse Current vs.
0
Vishay High Power Products
20
1
T
Notes:
1. Duty factor D = t
2. Peak T
3
Reverse Voltage (Per Leg)
J
V
= 100 °C
R
- Reverse Voltage (V)
J
P
6
= P
T
DM
J
10
= 75 °C
DM
t
1
T
x Z
J
t
2
1
= 50 °C
/t
9
thJC
2
T
+ T
J
= 25 °C
40L15CT
C
100
12
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15
3