32CTQ030-1PBF Vishay, 32CTQ030-1PBF Datasheet - Page 3

• Manufacturer Part Number: 32CTQ030-1PBF
• Description: DIODE SCHOTTKY 30V 15A TO262
• Manufacturer: Vishay

Specifications of 32CTQ030-1PBF

• Diode Configuration: 1 Pair Common Cathode
• Diode Type: Schottky
• Voltage - Forward (vf) (max) @ If: 580mV @ 30A
• Current - Reverse Leakage @ Vr: 1.75mA @ 30V
• Current - Average Rectified (io) (per Diode): 15A
• Voltage - Dc Reverse (vr) (max): 30V
• Speed: Fast Recovery =< 500ns, > 200mA (Io)
• Mounting Type: Through Hole, Radial
• Package / Case: I²Pak, TO-262 (3 straight leads + tab)
• Product: Schottky Rectifiers
• Peak Reverse Voltage: 30 V
• Forward Continuous Current: 30 A
• Max Surge Current: 900 A
• Configuration: Dual Common Cathode
• Forward Voltage Drop: 0.58 V
• Maximum Reverse Leakage Current: 1750 uA
• Operating Temperature Range: - 55 C to + 150 C
• Mounting Style: Through Hole
• Repetitive Reverse Voltage Vrrm Max: 30V
• Forward Current If(av): 30A
• Forward Voltage Vf Max: 580mV
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant
• Reverse Recovery Time (trr): -
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant, Lead free / RoHS Compliant
• Other names: *32CTQ030-1PBF

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1000
100
10
1
0
Fig. 1 - Max. Forward Voltage Drop Characteris-
0.2
0.01
0.1
0.00001
10
1
Forward Voltage Drop - V
0.4
D = 0.75
D = 0.50
D = 0.33
D = 0.25
D = 0.20
0.6
Fig. 4 - Max. Thermal Impedance Z
tics (Per Leg)
0.0001
0.8
T = 150°C
T = 125°C
T = 25°C
(T hermal Resistanc e)
J
J
J
1
S ingle Pulse
t , Rectangular Pulse Duration (S ec onds)
0.001
1
1.2
FM
1.4
(V)
1.6
0.01
1.8
thJC
40CTQ045, 40CTQ045S, 40CTQ045-1
0.1
Characteristics (Per Leg)
10000
Notes:
1. Duty fac tor D = t / t
2. Peak T = P
0.001
1000
1000
0.01
100
100
0.1
10
1
1
Fig. 2 - Typical Values Of Reverse Current
0
0
J
Fig. 3 - Typical Junction Capacitance
T = 150°C
5
Bulletin PD-20544 rev. D 07/06
J
Vs. Reverse Voltage (Per Leg)
Vs. Reverse Voltage (Per Leg)
P
DM
DM
10
125°C
100°C
10 15 20 25 30 35 40 45
R evers e Voltage - V (V)
R everse Voltage - V (V)
x Z
75°C
50°C
25°C
10
1 t
2 t
thJC
1
20
+ T
T = 25°C
2
J
C
100
30
R
R
40
3
50