40CPQ100 Vishay, 40CPQ100 Datasheet - Page 3

• Manufacturer Part Number: 40CPQ100
• Description: DIODE SCHOTTKY 100V 20A TO-247AC
• Manufacturer: Vishay

Specifications of 40CPQ100

• Voltage - Forward (vf) (max) @ If: 910mV @ 40A
• Current - Reverse Leakage @ Vr: 1.25mA @ 100V
• Current - Average Rectified (io) (per Diode): 20A
• Voltage - Dc Reverse (vr) (max): 100V
• Diode Type: Schottky
• Speed: Fast Recovery =< 500ns, > 200mA (Io)
• Diode Configuration: 1 Pair Common Cathode
• Mounting Type: Through Hole, Radial
• Package / Case: TO-247-3 (Straight Leads), TO-247AC
• Product: Schottky Rectifiers
• Peak Reverse Voltage: 100 V
• Forward Continuous Current: 40 A
• Max Surge Current: 2950 A
• Configuration: Dual Common Cathode
• Forward Voltage Drop: 0.91 V
• Maximum Reverse Leakage Current: 1250 uA
• Operating Temperature Range: - 55 C to + 175 C
• Mounting Style: Through Hole
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant
• Reverse Recovery Time (trr): -
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant, Lead free / RoHS Compliant
• Other names: *40CPQ100; VS-40CPQ100; VS-40CPQ100; VS40CPQ100; VS40CPQ100

Document Number: 93338
Revision: 21-Aug-08
Fig. 1 - Maximum Forward Voltage Drop Characteristics
0
0.001
0.01
0.1
10
0.00001
V
1
FM
0.4
- Forward Voltage Drop (V)
0.8
(Per Leg)
0.0001
Fig. 4 - Maximum Thermal Impedance Z
Fig. 3 - Typical Junction Capacitance vs. Reverse Voltage (Per Leg)
1.2
(thermal resistance)
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T
T
T
J
J
J
= 175 °C
= 125 °C
= 25 °C
Single pulse
Schottky Rectifier, 2 x 20 A
1.6
0.001
0
t
1
2.0
- Rectangular Pulse Duration (s)
20
V
R
- Reverse Voltage (V)
0.01
D = 0.50
D = 0.33
D = 0.25
D = 0.17
D = 0.08
40
T
J
= 25 °C
60
thJC
0.1
Characteristics (Per Leg)
80
Notes:
1. Duty factor D = t
2. Peak T
0
Fig. 2 - Typical Values of Reverse Current vs.
Vishay High Power Products
T
T
T
T
T
100
40CPQ080/40CPQ100
T
J
J
J
J
J
1
J
= 150 °C
= 100 °C
= 50 °C
= 125 °C
= 175 °C
= 75 °C
J
20
= P
Reverse Voltage (Per Leg)
V
R
DM
P
- Reverse Voltage (V)
DM
x Z
T
1
J
/t
40
t
1
thJC
= 25 °C
2
t
2
10
+ T
C
60
100
80
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100
3