LT1365 Linear Technology Corporation, LT1365 Datasheet - Page 6

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LT1365

Manufacturer Part Number
LT1365
Description
Dual And Quad 70mhz, 1000v/?s Op Amps
Manufacturer
Linear Technology Corporation
Datasheet

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LT1364/LT1365
TYPICAL PERFORMANCE CHARACTERISTICS
6
140
130
120
110
100
1.4
1.2
1.0
0.8
0.6
0.4
0.2
81
80
79
78
77
76
75
74
90
80
70
0
–50
– 50
–50
Input Bias Current vs
Temperature
Open-Loop Gain vs Temperature
Output Short-Circuit Current vs
Temperature
V
V
R
–25
S
O
–25
–25
L
= ±15V
= ±12V
= 1k
0
0
0
TEMPERATURE ( C)
TEMPERATURE ( C)
TEMPERATURE ( C)
SINK
25
25
25
SOURCE
50
50
50
V
I
B
S
=
= 15V
75
75
75
————
V
I
B
S
W
+ + I
= 5V
2
100
1364/1365 G04
100
1364/1365 G07
100
1364/1365 G10
B
U
125
125
125
100
10
–0.5
–1.0
–1.5
–2.0
–10
1
2.0
1.5
1.0
0.5
V
V
–2
–4
–6
–8
10
10
8
6
4
2
0
+
Input Noise Spectral Density
0
0
Output Voltage Swing vs
Supply Voltage
Settling Time vs Output Step
(Noninverting)
i
n
V
A
R
S
V
L
T
= 15V
= 1
= 1k
A
100
20
10mV
= 25 C
e
5
SUPPLY VOLTAGE ( V)
n
FREQUENCY (Hz)
SETTLING TIME (ns)
40
10mV
1k
10
1mV
R
R
L
60
L
= 500
= 500
V
T
A
R
A
S
V
10k
S
= 15V
= 25 C
= 101
= 100k
R
R
15
1mV
L
L
1364/1365 G05
80
= 1k
= 1k
1364/1365 G08
1364/1365 G11
100k
100
20
10
1
0.1
–0.5
–1.0
–1.5
–2.0
–10
2.0
1.5
1.0
0.5
V +
V –
–4
–6
–8
85
80
75
70
65
60
10
–2
8
6
4
2
0
–50 –40
10
0
Open-Loop Gain vs
Resistive Load
Output Voltage Swing vs
Load Current
Settling Time vs Output Step
(Inverting)
V
V
T
V
A
R
C
S
IN
A
V
S
V
F
F
= 5V
= 25 C
S
= 100mV
= 3pF
= 15V
= –1
= 1k
25 C
= 15V
–30
20
OUTPUT CURRENT (mA)
LOAD RESISTANCE ( )
–20
10mV
SETTLING TIME (ns)
100
85 C
–10
40
25 C
10mV
–40 C
0
10 20
60
1k
1mV
V
1mV
S
= 5V
–40 C
85 C
30 40 50
80
1364/1365 G06
1364/1365 G09
1364/1365 G12
100
10k

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