lt3510 Linear Technology Corporation, lt3510 Datasheet - Page 12

• Manufacturer Part Number: lt3510
• Description: Monolithic Dual Tracking 2a Step-down Switching Regulator
• Manufacturer: Linear Technology Corporation

applicaTions inForMaTion
LT3510
maximum duty cycle. The duty cycle is the fraction of time
that the internal switch is on during a clock cycle. Unlike
most fixed frequency regulators, the LT3510 will not switch
off at the end of each clock cycle if there is sufficient volt-
age across the boost capacitor (C3 in Figure 1) to fully
saturate the output switch. Forced switch off for a minimum
time will only occur at the end of a clock cycle when the
boost capacitor needs to be recharged. This operation
has the same effect as lowering the clock frequency for a
fixed off time, resulting in a higher duty cycle and lower
minimum input voltage. The resultant duty cycle depends
on the charging times of the boost capacitor and can be
approximated by the following equation:
where B is 2A divided by the typical boost current from
the Electrical Characteristics.
This leads to a minimum input voltage of:
where V
Figure 3 shows a typical graph of minimum input voltage
vs load current for the 3.3V and 1.8V application on the
first page of this data sheet. The maximum input voltage
is determined by the absolute maximum ratings of the V
and BST pins and by the frequency and minimum duty
cycle. The minimum duty cycle is defined as :
Maximum input voltage as:
Note that the LT3510 will regulate if the input voltage is
taken above the calculated maximum voltage as long as
maximum ratings of the V
However operation in this region of input voltage will exhibit
pulse skipping behavior.

DC
Dc
V
V
IN MIN
IN MAX
MIN
MAX
(
(
SW
= t
)
=
)
=
is the voltage drop of the internal switch.
=
ON(MIN)
1
V
+
V
1
OUT
Dc
OUT
Dc
B
1
MAX
MIN
+
• Frequency
+
V
V
D
D
–
IN
–
V
and BST pins are not violated.
V
D
D
+
+
V
V
SW
SW
IN
Example:
V
= 25°C
V
specification), V
Inductor Selection and Maximum Output Current
A good first choice for the inductor value is:
where f is frequency in MHz and L is in µH.
With this value the maximum load current will be ~2A,
independent of input voltage. The inductor’s RMS current
rating must be greater than your maximum load current
OUT
SW
Dc
Dc
L
V
V
IN MIN
IN MAX
=
= 0.1V, B = 40 (from from boost characteristics
= 3.3V, I
MAX
MIN
(
(
Figure 3. Minimum Input Voltage vs Load Current
(
V
IN
)
=
6.0
5.5
5.0
4.5
4.0
3.5
3.0
=
)
=
–
=
t
1
1
MIN ON
V
OUT
3 3 0 4
V
V
+
3 3
OUT
OUT
.
IN
1
.
0 98
0 200
D
(
40
= 3.3V
.
.
1
+
•
= 1A, Frequency = 1MHz, Temperature
= 0.4V, t
+
)
f
)
10
0 0 4
=
•
.
•
.
V
98
f
CURRENT (mA)
OUT
– .
=
– .
RUNNING
START-UP
%
0 4 0
0 200
ON(MIN)
0 4 0 1 18 2
100
.
+
+
.
1 1 3 48
.
1000
= 200ns
=
=
.
3510 F03
.
10000
V
V
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