JC100A Lineage Power, JC100A Datasheet - Page 12
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JC100A
Manufacturer Part Number
JC100A
Description
CONVERTER DC/DC 5V 100W OUT
Manufacturer
Lineage Power
Series
JC100r
Type
Isolated with Remote On/Offr
Datasheet
1.JC050A1.pdf
(16 pages)
Specifications of JC100A
Output
5V
Number Of Outputs
1
Power (watts)
100W
Mounting Type
Through Hole
Voltage - Input
18 ~ 36V
Package / Case
9-DIP Module
1st Output
5 VDC @ 20A
Size / Dimension
2.40" L x 2.28" W x 0.50" H (61mm x 57.9mm x 12.7mm)
Power (watts) - Rated
100W
Operating Temperature
-40°C ~ 100°C
Efficiency
85%
Approvals
CSA, UL, VDE
Product
Isolated
Output Power
100 W
Input Voltage Range
18 V to 36 V
Input Voltage (nominal)
28 V
Output Voltage (channel 1)
5 V
Output Current (channel 1)
20 A
Isolation Voltage
1.5 KV
Package / Case Size
DIP
Output Type
Isolated
Output Voltage
5 V
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
3rd Output
-
2nd Output
-
4th Output
-
Lead Free Status / Rohs Status
No
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
JC100A1
Manufacturer:
LUCENT
Quantity:
27
Part Number:
JC100A1
Manufacturer:
LUCENT
Quantity:
20 000
Part Number:
JC100A1
Quantity:
55
18 Vdc to 36 Vdc Input, 5 Vdc Output; 50 W to 100 W
12
12
Thermal considerations
Heat Transfer Without Heat Sinks
Increasing airflow over the module enhances the heat
transfer via convection. Figure 24 shows the maximum
power that can be dissipated by the module without
exceeding the maximum case temperature versus local
ambient temperature (T
through 4 m/s (800 ft./min.).
Note that the natural convection condition was mea-
sured at 0.05 m/s to 0.1 m/s (10 ft./min. to 20 ft./min.);
however, systems in which these power modules may
be used typically generate natural convection airflow
rates of 0.3 m/s (60 ft./min.) due to other heat dissipat-
ing components in the system. The use of Figure 24 is
shown in the following example.
Example
What is the minimum airflow necessary for a JC100A
operating at nominal line, an output current of 20 A,
and a maximum ambient temperature of 40 °C?
Solution
Given: V
Determine P
Determine airflow (v) (Use Figure 24.):
Figure 24. Forced Convection Power Derating with
35
30
25
20
15
10
5
0
0
I
T
P
v = 2.7 m/s (540 ft./min.)
O
A
I
D
= 20 A
= 28 V
= 40 °C
= 22.8 W
0.1 m/s (NAT. CONV.)
10
No Heat Sink; Either Orientation
D
(Use Figure 27.):
LOCAL AMBIENT TEMPERATURE, T
20
(20 ft./min.)
30
A
) for natural convection
40
50
(continued)
60
4.0 m/s (800 ft./min
3.5 m/s (700 ft./min
3.0 m/s (600 ft./min
2.5 m/s
2.0 m/s
1.5 m/s (300 ft./min
1.0 m/s (200 ft./min
0.5 m/s (100 ft./min
70
(500 ft./min
(400 ft./min
A
80
(˚C)
8-1150 (C).a
90
100
Figure 25. JC050A Power Dissipation vs.
Figure 26. JC075A Power Dissipation vs.
Figure 27. JC100A Power Dissipation vs.
24
22
20
18
16
14
12
10
12
11
10
20
18
16
14
12
10
8
6
4
2
0
9
8
7
6
5
4
8
6
4
2
0
1
0
0
1
2
Output Current
Output Current
Output Current
2
2
4
3
3
OUTPUT CURRENT, I
V
V
V
4
OUTPUT CURRENT, I
I
I
OUTPUT CURRENT, I
I
6
= 27 V
= 18 V
V
V
V
V
V
V
= 36 V
I
I
I
I
I
I
4
5
= 36 V
= 28 V
= 18 V
= 18 V
= 28 V
= 36 V
8
6
5
7
10
Lineage Power
8
March 2008
6
12
9
O
O
(A)
O
10
7
(A)
14
(A)
11
16
8
12
13
18
9
14
8-2220
8-1604
8-1605
20
15
10