QW050F1 Lineage Power, QW050F1 Datasheet - Page 15

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QW050F1

Manufacturer Part Number
QW050F1
Description
CONVERTER DC/DC 3.3V 33W OUT
Manufacturer
Lineage Power
Series
QWr
Type
Isolated with Remote On/Offr
Datasheet

Specifications of QW050F1

Output
3.3V
Number Of Outputs
1
Power (watts)
33W
Mounting Type
Through Hole
Voltage - Input
36 ~ 75V
Package / Case
8-DIP Module
1st Output
3.3 VDC @ 10A
Size / Dimension
2.28" L x 1.45" W x 0.50" H (57.9mm x 36.8mm x 12.7mm)
Power (watts) - Rated
33W
Operating Temperature
-40°C ~ 100°C
Efficiency
81%
Approvals
CE, CSA, UL, VDE
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
3rd Output
-
2nd Output
-
4th Output
-

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Thermal Considerations
Heat Transfer with Heat Sinks
Example
If an 85 °C case temperature is desired, what is the
minimum airflow necessary? Assume the QW075F1
module is operating at V
of 10 A, transverse orientation, maximum ambient air
temperature of 40 °C, and the heat sink is 1/2 inch.
Solution
Given: V
Determine P
Then solve the following equation:
Use Figure 26 to determine air velocity for the 1/2 inch
heat sink.
The minimum airflow necessary for the QW050F1
module is 0.4 m/s (70 ft./min.).
Note: Pending improvement will lower the power dissi-
Lineage Power
θ
θ
θ
ca
ca
ca
pation and reduce the airflow needed.
I
T
T
Heat sink = 1/2 inch
P
O
=
=
=
A
C
I
D
= 10 A
= 54 V
= 40 °C
= 85 °C
= 8.8 W
5.1 °C/W
D
(
----------------------- -
(
----------------------- -
T
85 40
by using Figure 24:
C
8.8
P
D
T
A
)
)
I
= 54 V and an output current
dc-dc Converters; 36 to 75 Vdc Input, 3.3 Vdc Output; 33 W to 50 W
(continued)
(continued)
Custom Heat Sinks
A more detailed model can be used to determine the
required thermal resistance of a heat sink to provide
necessary cooling. The total module resistance can be
separated into a resistance from case-to-sink (θcs) and
sink-to-ambient (θsa) as shown in Figure 32.
Figure 32. Resistance from Case-to-Sink and
For a managed interface using thermal grease or foils,
a value of θcs = 0.1 °C/W to 0.3 °C/W is typical. The
solution for heat sink resistance is:
This equation assumes that all dissipated power must
be shed by the heat sink. Depending on the user-
defined application environment, a more accurate
model, including heat transfer from the sides and bot-
tom of the module, can be used. This equation pro-
vides a conservative estimate for such instances.
EMC Considerations
For assistance with designing for EMC compliance,
please refer to the FLTR100V10 data sheet
(DS99-294EPS).
Layout Considerations
Copper paths must not be routed beneath the power
module mounting inserts. For additional layout guide-
lines, refer to the FLTR100V10 data sheet
(DS99-294EPS).
θsa
P
=
D
Sink-to-Ambient
(
----------------------- -
T
C
T
P
C
D
T
A
)
θcs
θcs
T
S
θsa
T
A
8-1304 (C)
15

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