LM2737MTC National Semiconductor, LM2737MTC Datasheet - Page 12

• Manufacturer Part Number: LM2737MTC
• Description: IC,SMPS CONTROLLER,VOLTAGE-MODE,BICMOS,TSSOP,14PIN,PLASTIC
• Manufacturer: National Semiconductor

Specifications of LM2737MTC

• Rohs Compliant: NO

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Application Information
In this example, in order to maintain a 2% peak-to-peak
output voltage ripple and a 40% peak-to-peak inductor cur-
rent ripple, the required maximum ESR is 6mΩ. Three Sanyo
10MV5600AX capacitors in parallel will give an equivalent
ESR of 6mΩ. The total bulk capacitance of 16.8mF is
enough to supply even severe load transients. Using the
same capacitors for both input and output also keeps the bill
of materials simple.
MOSFETS
MOSFETS are a critical part of any switching controller and
have a direct impact on the system efficiency. In this case
the target efficiency is 85% and this is the variable that will
determine which devices are acceptable. Loss from the ca-
pacitors, inductors, and the LM2727 itself are detailed in the
Efficiency section, and come to about 0.54W. To meet the
target efficiency, this leaves 1.45W for the FET conduction
loss, gate charging loss, and switching loss. Switching loss
is particularly difficult to estimate because it depends on
many factors. When the load current is more than about 1 or
2 amps, conduction losses outweigh the switching and gate
charging losses. This allows FET selection based on the
R
charging losses to the equation leaves 1.2W for conduction
losses. The equation for conduction loss is:
The factor k is a constant which is added to account for the
increasing R
Si4442DY has a typical R
the equation for P
design were for a 5V to 2.5V circuit, an equal number of
FETs on the high and low sides would be the best solution.
With the duty cycle D = 0.24, it becomes apparent that the
low side FET carries the load current 76% of the time.
Adding a second FET in parallel to the bottom FET could
improve the efficiency by lowering the effective R
lower the duty cycle, the more effective a second or even
third FET can be. For a minimal increase in gate charging
loss (0.054W) the decrease in conduction loss is 0.15W.
What was an 85% design improves to 86% for the added
cost of one SO-8 MOSFET.
CONTROL LOOP COMPONENTS
The circuit is this design example and the others shown in
the Example Circuits section have been compensated to
improve their DC gain and bandwidth. The result of this
compensation is better line and load transient responses.
For the LM2727, the top feedback divider resistor, Rfb2, is
also a part of the compensation. For the 10A, 5V to 1.2V
design, the values are:
Cc1 = 4.7pF 10%, Cc2 = 1nF 10%, Rc = 229kΩ 1%. These
values give a phase margin of 63˚ and a bandwidth of
29.3kHz.
SUPPORT CAPACITORS AND RESISTORS
The Cinx capacitors are high frequency bypass devices,
designed to filter harmonics of the switching frequency and
input noise. Two 1µF ceramic capacitors with a sufficient
voltage rating (10V for the Circuit of Figure 3) will work well
in almost any case.
DSON
P
Cnd
of the FET. Adding the FET switching and gate-
= D(I
DSON
2
o
of a FET due to heating. Here, k = 1.3. The
CND
* R
DSON
the result is a loss of 0.533W. If this
DSON
*k) + (1-D)(I
of 4.1mΩ. When plugged into
2
o
(Continued)
* R
DSON
DSON
*k)
. The
12
Rbypass and Cbypass are standard filter components de-
signed to ensure smooth DC voltage for the chip supply and
for the bootstrap structure, if it is used. Use 10Ω for the
resistor and a 2.2µF ceramic for the cap. Cb is the bootstrap
capacitor, and should be 0.1µF. (In the case of a separate,
higher supply to the BOOTV pin, this 0.1µF cap can be used
to bypass the supply.) Using a Schottky device for the boot-
strap diode allows the minimum drop for both high and low
side drivers. The On Semiconductor BAT54 or MBR0520
work well.
Rp is a standard pull-up resistor for the open-drain power
good signal, and should be 10kΩ. If this feature is not
necessary, it can be omitted.
R
design calls for a peak current magnitude (Io + 0.5 * ∆I
12A, a safe setting would be 15A. (This is well below the
saturation current of the output inductor, which is 25A.)
Following the equation from the Current Limit section, use a
3.3kΩ resistor.
R
Following the equation in the Theory of Operation section,
the closest 1% tolerance resistor to obtain f
88.7kΩ.
C
equation for C
3ms delay, a 12nF capacitor will suffice.
EFFICIENCY CALCULATIONS
A reasonable estimation of the efficiency of a switching
controller can be obtained by adding together the loss is
each current carrying element and using the equation:
The following shows an efficiency calculation to complement
the Circuit of Figure 3. Output power for this circuit is 1.2V x
10A = 12W.
Chip Operating Loss
2mA x 5V = 0.01W
FET Gate Charging Loss
The value n is the total number of FETs used. The Si4442DY
has a typical total gate charge, Q
4.1mΩ.
2*5*36E
FET Switching Loss
The Si4442DY has a typical rise time t
and 47ns, respectively. 0.5*5*10*58E
CS
FADJ
SS
is the resistor used to set the current limit. Since the
depends on the users requirements. Based on the
is used to set the switching frequency of the chip.
-9
*300,000 = 0.108W
For
P
SW
SS
P
a
GC
= 0.5 * V
in the Theory of Operation section, for a
single
= n * V
P
IQ
= I
in
Q-V CC
CC
FET
* I
O
* Q
GS
* (t
*V
GS
on
, of 36nC and an r
r
CC
-9
+ t
* f
r
*300,000 = 0.435W
f
and fall time t
OSC
top
)* f
OSC
SW
and
= 300kHz is
bottom:
ds-on
f
of 11
o
) of
of