IR3082AMPBF International Rectifier, IR3082AMPBF Datasheet - Page 28

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IR3082AMPBF

Manufacturer Part Number
IR3082AMPBF
Description
IC XPHASE CONTROL 9.6V 20-MLPQ
Manufacturer
International Rectifier
Series
XPhase™r
Datasheet

Specifications of IR3082AMPBF

Applications
Processor
Current - Supply
12mA
Voltage - Supply
8.05 V ~ 16 V
Operating Temperature
0°C ~ 100°C
Mounting Type
Surface Mount
Package / Case
20-MLPQ
Ic Function
Control IC
Supply Voltage Range
8.05V To 16V
Operating Temperature Range
0°C To +100°C
Digital Ic Case Style
MLPQ
No. Of Pins
20
Peak Reflow Compatible (260 C)
Yes
Frequency
1MHz
Rohs Compliant
Yes
Controller Type
PWM
Filter Terminals
SMD
Package
20-Lead MLPQ
Circuit
X-Phase Control IC
Switch Freq (khz)
150kHz to 1.0MHz
Pbf
PbF Option Available
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
VOLTAGE LOOP COMPENSATION
All ceramic output capacitors are used in the design, type III compensation as shown in Figure 18(b) is used here.
Choose the desired crossover frequency fc =80 kHz and determine Rcp and C
Choose C
CURRENT SHARE LOOP COMPENSATION
The crossover frequency of the current share loop f
loop f
Choose C
C
C
C
R
R
F
CP
MI
SCOMP
CP
FB
FB
1
C
2 (
(
10
R
4
V
. Choose the crossover frequency of current share loop f
1
2
S
S
PWMRMP
I
Page 28 of 33
˜
˜
. 0

˜
˜
R
CP1
12
SCOMP
. 0
R
f
f
V
65
FB
L
C
C
1
PWMRMP
CP
4 .
65
)
E
˜
˜
2
=220pF to reduce high frequency noise.
nF
R
˜
˜
R
˜
˜
C
C
18
L
PWMRMP
1
2
FB
PWMRMP
E
E
=22nF
1
˜
2 .
˜
230

C
V
˜
o
V
10
E
10
4
DAC
˜
S
˜
R
V
3
˜
˜
115
FB
˜
I
˜
f
)
12
80
SW
˜
˜
(
˜
I
(
220
V
V
O
:
˜
˜
˜
1
10
V
100
PWMRMP
I
˜
G

PWMRMP
˜
3
V
10
CS
V
˜
O
˜
100
DAC
34
. 2
_
˜
ROOM
2
9
31
Choose R
˜
S
)
/
(
2 (
) 5
. 0
˜
˜
10
. 1 (
. 8
f
42
S
˜
18
˜
CI
(
R
3
54
33
˜
47
˜
80
2 .
LE
˜
10
(
. 1
nF
12

˜
˜
˜
˜
05
10
10
1 [
10
100
FB1
3

, choose C

3
˜
3
10
) 5
0
6
)
˜
=100
2
100
8 .
2
˜
˜
S
6
˜
7
32
˜
1 [

(
5 .
˜
220
)
. 1

˜
f
˜
10
CI
10
CI
35
2
S
˜
˜
10
35
12
)
C
should be at least one decade lower than that of the voltage
4
˜
˜
FB
10
E
)
. 1
2 .
˜
(
12
9
600
˜
˜
335
nF
=10nF
/
2
(
˜
) 5
V
10
S

O
˜
. 1
˜
˜
, Choose C
10
3
10
(
I
47
35
˜
CI
O
1504
3
˜
)]
˜
10
)
˜
=10kHz
0
10
˜
8 .
F
3
˜
MI
6
˜
10
. 1
˜
32
05
. 0
6
CP
011
)
,
˜
˜
˜
and calculate C
10
. 1 (
230
=33nF
33
6
˜
CP
0

8 .
100
:
. 2
˜
7
31
5 .
k
˜
:
10
SCOMP
4
)
100
05/02/2006
,
IR3082A
]
˜
. 0
011

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