SAF-XC164N-16F40F BB Infineon Technologies, SAF-XC164N-16F40F BB Datasheet - Page 59

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SAF-XC164N-16F40F BB

Manufacturer Part Number
SAF-XC164N-16F40F BB
Description
IC MCU 16BIT 128KB TQFP-100-16
Manufacturer
Infineon Technologies
Series
XC16xr
Datasheet

Specifications of SAF-XC164N-16F40F BB

Core Processor
C166SV2
Core Size
16-Bit
Speed
40MHz
Connectivity
EBI/EMI, SPI, UART/USART
Peripherals
PWM, WDT
Number Of I /o
79
Program Memory Size
128KB (128K x 8)
Program Memory Type
FLASH
Ram Size
8K x 8
Voltage - Supply (vcc/vdd)
2.35 V ~ 2.7 V
Oscillator Type
Internal
Operating Temperature
-40°C ~ 85°C
Package / Case
100-LFQFP
For Use With
MCBX167-NET - BOARD EVAL INFINEON CAN/ETHRNTMCBXC167-BASIC - BOARD EVAL BASIC INFINEON XC16X
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Eeprom Size
-
Data Converters
-
Other names
SAFXC164N16F40FBB
SP000094302
SP000224574
generation or measurement, lower baudrates, etc.) the deviation caused by the PLL jitter
is negligible.
The value of the accumulated PLL jitter depends on the number of consecutive VCO
output cycles within the respective timeframe. The VCO output clock is divided by the
output prescaler (K = PLLODIV+1) to generate the master clock signal
the number of VCO cycles can be represented as K × N, where N is the number of
consecutive
For a period of N × TCM the accumulated PLL jitter is defined by the deviation D
D
So, for a period of 3 TCMs @ 20 MHz and K = 12: D
This formula is applicable for K × N < 95. For longer periods the K × N = 95 value can be
used. This steady value can be approximated by: D
Figure 14
Note: The bold lines indicate the minimum accumulated jitter which can be achieved by
Different frequency bands can be selected for the VCO, so the operation of the PLL can
be adjusted to a wide range of input and output frequencies:
Data Sheet
N
[ns] = ±(1.5 + 6.32 × N /
selecting the maximum possible output prescaler factor K.
Acc. jitter
±8
±7
±6
±5
±4
±3
±2
±1
ns
f
0
MC
Approximated Accumulated PLL Jitter
0
cycles (TCM).
1
10 MHz
40 MHz
D
N
K = 15
5
20 MHz
f
MC
K = 12
);
f
MC
K = 10
10
in [MHz], N = number of consecutive TCMs.
K = 8
57
K = 6 K = 5
15
Nmax
3
= ±(1.5 + 6.32 × 3 / 20) = 2.448 ns.
[ns] = ±(1.5 + 600 / (K ×
20
Electrical Parameters
25
MCD05566
f
MC
Derivatives
V1.2, 2006-08
. Therefore,
N
XC164N
N
f
MC
:
)).

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