HCPL-2612-300E Avago Technologies US Inc., HCPL-2612-300E Datasheet - Page 10
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HCPL-2612-300E
Manufacturer Part Number
HCPL-2612-300E
Description
OPTOCOUPLER, TRANSISTOR, 3750VRMS
Manufacturer
Avago Technologies US Inc.
Datasheet
1.HCPL-2612-000E.pdf
(16 pages)
Specifications of HCPL-2612-300E
No. Of Channels
1
Optocoupler Output Type
Logic Gate
Input Current
60mA
Output Voltage
5.5V
Opto Case Style
SMD
No. Of Pins
8
Peak Reflow Compatible (260 C)
Yes
Isolation Voltage
3.75kV
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
HCPL-2612-300E
Manufacturer:
AVAGO
Quantity:
40 000
Figure 10. Test circuit for t
Figure 6. Test circuit for t
10
Figure 8. Typical propagation delay vs. pulse
input current.
PULSE GEN.
t = t = 5 ns
MONITORING
f
Z
105
O
90
75
60
45
30
7.5 mA
= 50
r
PULSE GEN.
t = t = 5 ns
OUTPUT
5
I
f
INPUT
*C
NODE
Z
I
t
INPUT
PHL
I
O
V
T
I
L
CC
A
– PULSE INPUT CURRENT – mA
V
= 50
IS APPROXIMATELY 15 pF WHICH INCLUDES
PROBE AND STRAY WIRING CAPACITANCE.
V
r
E
OUTPUT
= 25°C
O
, R
= 5 V
INPUT
7
*C
R
I
t
L
I
M
PLH
L
V
1
2
3
4
= 350
I
I
O
IS APPROXIMATELY 15 pF WHICH INCLUDES
PROBE AND STRAY WIRING CAPACITANCE.
1 K
4 K
, R
MONITORING NODE
9
t
EHL
L
1
2
3
4
= 350
t
PHL
INPUT V
t
PLH
PLH
EHL
t
11
and t
PHL
and t
, R
, R
L
L
PLH
E
ELH
= 1 K
= 4 K
13
.
.
GND
V
CC
t
ELH
8
7
6
5
GND
15
V
CC
t
PLH
7
8
6
5
0.1 µF
BYPASS
Figure 9. Typical pulse width distortion vs.
temperature.
*C
-10
1.5 V
L
3.0 V
1.5 V
30
20
10
40
+5 V
0.1µF
BYPASS
0
-60
R
*C
1.5 V
L
I
I
I
I
-40
L
+5 V
OUTPUT V
MONITORING
NODE
= 7.50 mA
= 3.75 mA
R
T
R
R
A
L
-20
L
L
= 350 k
– TEMPERATURE – °C
= 4 k
OUTPUT V
MONITORING
NODE
0
O
R
20
L
= 1 k
O
40
V
I
I
CC
= 7.5 mA
60
= 5 V
80
100
Figure 7. Typical propagation delay vs.
temperature.
Figure 11. Typical enable propagation delay
vs. temperature.
100
120
80
60
40
20
90
60
30
0
0
-60
-60
t
V
I
V
V
V
I
PHL
I
I
CC
CC
EH
EL
= 7.5 mA
= 7.5 mA
-40
-40
t
= 0 V
, R
= 3 V
= 5 V
PLH
T
= 5 V
T
A
A
-20
-20
L
– TEMPERATURE – °C
– TEMPERATURE – °C
t
t
t
= 350
, R
EHL
ELH
ELH
1 K
4 K
L
0
0
, R
t
, R
, R
= 350
PLH
L
L
L
20
20
= 350
= 4 k
= 1 k
, R
t
PLH
t
ELH
40
L
40
= 1 K
, R
, R
60
1 k
60
L
L
= 4 K
= 350
80
80
4 k
100
100