ACPL-214-50AE Avago Technologies US Inc., ACPL-214-50AE Datasheet - Page 4
ACPL-214-50AE
Manufacturer Part Number
ACPL-214-50AE
Description
NPN-Output Ac-Input Optocoupler,1-CHANNEL,3kV ISOLATION,SO
Manufacturer
Avago Technologies US Inc.
Datasheet
1.ACPL-214-50AE.pdf
(7 pages)
Specifications of ACPL-214-50AE
Number Of Channels
1
Input Type
AC, DC
Voltage - Isolation
3000Vrms
Current Transfer Ratio (min)
50% @ ±1mA
Current Transfer Ratio (max)
250% @ ±1mA
Voltage - Output
80V
Current - Output / Channel
50mA
Current - Dc Forward (if)
±50mA
Vce Saturation (max)
400mV
Output Type
Transistor
Mounting Type
Surface Mount
Package / Case
SO-4
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Electrical Specifications
Over recommended ambient temperature at 25ºC unless otherwise specified.
Figure 1. Switching Time Test Circuit
Figure 2. Frequency Response Test Circuit
4
I
F
Parameter
Forward Voltage
Terminal Capacitance
Collector Dark Current
Collector-Emitter Breakdown
Voltage
Emitter-Collector Breakdown
Voltage
Current Transfer Ratio
Saturated CTR
Collector-Emitter Saturation
Voltage
Isolation Resistance
Floating Capacitance
Cut-off Frequency (-3dB)
Response Time (Rise)
Response Time (Fall)
Turn-on Time
Turn-off Time
Turn-ON Time
Storage Time
Turn-OFF Time
Common Mode Rejection
Voltage
R
D
R
L
V
V
CC
CE
R
L
Symbol
V
C
I
BV
BV
CTR
CTR
V
Riso
C
F
t
t
t
t
t
T
t
CMR
CEO
r
f
on
off
ON
OFF
Output
C
S
F
t
CE
F
V
V
CEO
ECO
(sat)
(sat)
I
I
CE
CE
V
F
F
CC
Min.
-
-
-
80
7
20
-
-
5x10
-
-
-
-
-
-
-
-
-
-
t
t
on
on
10
t
t
r
r
Typ.
1.2
60
-
-
-
-
100
-
1x10
0.8
80
2
3
3
3
2
25
40
10
t
t
t
t
t
t
f
f
s
s
off
off
11
Max.
1.4
-
100
-
-
400
-
0.4
-
1
-
-
-
-
-
-
-
-
-
90%
90%
10%
10%
Units
V
pF
nA
V
V
%
%
V
:
pF
kHz
Ps
Ps
Ps
Ps
Ps
Ps
Ps
kV/Ps
Test Conditions
I
V = 0, f = 1MHz
V
I
I
I
I
I
DC500V, R.H. 40~60%
V = 0, f = 1MHz
V
R
V
R
VCC = 5V, I
R
Ta=25ºC, R
V
V
F
C
E
F
F
F
L
L
L
CE
CC
CC
CM
CC
= ±20mA
= 100 PA, I
= ±1 mA, V
= ±1mA, V
= ±8mA, I
= 0.5 mA, I
= 100:
= 100:
= 1.9k:
=9V, V
= 48V, I
= 5V, I
= 10V, I
=1.5kV(peak), I
np
C
F
L
F
C
=470:,
C
= 2 mA,
=100mV
= 16 mA,
CE
= 0 mA
F
F
CE
= 2 mA,
= 2.4mA
= 0 mA
= 0 mA
= 0.4V
= 5V
F
=0mA,
Note
Fig.6
Fig.12
CTR=(I
100%
Fig.14
Fig. 2,19
Fig. 1
Fig. 1, 17
Fig.20
C
/I
F
)x