2N6039 ON Semiconductor, 2N6039 Datasheet - Page 3

Darlington Transistors 4A 80V Bipolar

2N6039

Manufacturer Part Number
2N6039
Description
Darlington Transistors 4A 80V Bipolar
Manufacturer
ON Semiconductor
Datasheet

Specifications of 2N6039

Configuration
Single
Transistor Polarity
NPN
Mounting Style
Through Hole
Package / Case
TO-225-3
Collector- Emitter Voltage Vceo Max
80 V
Emitter- Base Voltage Vebo
5 V
Collector- Base Voltage Vcbo
80 V
Maximum Dc Collector Current
4 A
Maximum Collector Cut-off Current
500 uA
Power Dissipation
40 W
Maximum Operating Temperature
+ 150 C
Continuous Collector Current
4 A
Dc Collector/base Gain Hfe Min
100, 500, 750
Minimum Operating Temperature
- 65 C
Lead Free Status / RoHS Status
Lead free / RoHS Compliant

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
2N6039
Manufacturer:
ON
Quantity:
1 350
Part Number:
2N6039
Manufacturer:
ST
0
Part Number:
2N60398
Manufacturer:
ST
0
Part Number:
2N6039G
Manufacturer:
ON
Quantity:
500
approx
+ 8.0 V
approx
-12 V
V
V
R
D
t
DUTY CYCLE = 1.0%
2
1
r
1N5825 USED ABOVE I
MSD6100 USED BELOW I
, t
B
1
0.07
0.05
0.03
0.02
0.01
0
f
MUST BE FAST RECOVERY TYPE, eg:
1.0
0.7
0.5
0.3
0.2
0.1
& R
≤ 10 ns
0.01
C
VARIED TO OBTAIN DESIRED CURRENT LEVELS
Figure 1. Switching Times Test Circuit
SINGLE PULSE
D = 0.5
0.05
0.02
0.02 0.03
0.1
0.2
25 ms
B
0.05
≈ 100 mA
B
0.01
≈ 100 mA
51
for t
and V
to obtain desired test currents.
For NPN test circuit, reverse diode,
polarities and input pulses.
0.1
d
and t
2
R
= 0, R
D
B
1
+ 4.0 V
r
, D
0.2
B
1
is disconnected
and R
0.3
≈ 8.0 k
C
are varied
0.5
TUT
≈ 60
Figure 3. Thermal Response
R
C
- 30 V
http://onsemi.com
V
1.0
CC
SCOPE
2.0
t, TIME (ms)
3
3.0
4.0
2.0
1.0
0.8
0.6
0.4
0.2
q
q
D CURVES APPLY FOR POWER
PULSE TRAIN SHOWN
READ TIME AT t
T
JC
JC
J(pk)
5.0
0.04
(t) = r(t) q
= 3.12°C/W MAX
- T
0.06
C
10
= P
JC
(pk)
0.1
PNP
NPN
1
q
20
Figure 2. Switching Times
JC
I
C
(t)
, COLLECTOR CURRENT (AMP)
30
0.2
t
s
50
P
0.4
(pk)
DUTY CYCLE, D = t
100
V
I
C
CC
0.6
/I
t
1
B
= 30 V
= 250
t
2
200
1.0
300
t
d
I
T
B1
J
@ V
t
= 25°C
f
= I
1
2.0
/t
BE(off)
B2
500
2
t
r
= 0
1000
4.0

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