IRFL024ZTRPBF International Rectifier, IRFL024ZTRPBF Datasheet - Page 7

• Manufacturer Part Number: IRFL024ZTRPBF
• Description: MOSFET N-CH 55V 5.1A SOT223
• Manufacturer: International Rectifier
• Series: HEXFET®r

Specifications of IRFL024ZTRPBF

• Package / Case: SOT-223 (3 leads + Tab), SC-73, TO-261
• Mounting Type: Surface Mount
• Power - Max: 1W
• Fet Type: MOSFET N-Channel, Metal Oxide
• Gate Charge (qg) @ Vgs: 14nC @ 10V
• Vgs(th) (max) @ Id: 4V @ 250µA
• Current - Continuous Drain (id) @ 25° C: 5.1A
• Drain To Source Voltage (vdss): 55V
• Fet Feature: Logic Level Gate
• Rds On (max) @ Id, Vgs: 57.5 mOhm @ 3.1A, 10V
• Transistor Polarity: N Channel
• Continuous Drain Current Id: 5.1A
• Drain Source Voltage Vds: 55V
• On Resistance Rds(on): 57.5mohm
• Rds(on) Test Voltage Vgs: 10V
• Peak Reflow Compatible (260 C): Yes
• Rohs Compliant: Yes
• Lead Free Status / RoHS Status: Lead free / RoHS Compliant

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0.01
0.1
10
14
12
10
1.0E-05
1
8
6
4
2
0
Fig 16. Maximum Avalanche Energy
25
Starting T J , Junction Temperature (°C)
Duty Cycle = Single Pulse
0.05
0.10
50
0.01
vs. Temperature
TOP
BOTTOM 1% Duty Cycle
I D = 3.1A
1.0E-04
75
Fig 15. Typical Avalanche Current vs.Pulsewidth
Single Pulse
100
1.0E-03
125
150
tav (sec)
Notes on Repetitive Avalanche Curves , Figures 15, 16:
(For further info, see AN-1005 at www.irf.com)
1. Avalanche failures assumption:
2. Safe operation in Avalanche is allowed as long asT
3. Equation below based on circuit and waveforms shown in
4. P
5. BV = Rated breakdown voltage (1.3 factor accounts for
6. I
7. T
1.0E-02
t
Purely a thermal phenomenon and failure occurs at a
temperature far in excess of T
every part type.
not exceeded.
Figures 12a, 12b.
avalanche pulse.
voltage increase during avalanche).
T
D = Duty cycle in avalanche = t
Z
av =
av
thJC
jmax
D (ave)
= Allowable avalanche current.
=
Average time in avalanche.
(D, t
Allowable rise in junction temperature, not to exceed
(assumed as 25°C in Figure 15, 16).
= Average power dissipation per single
av
P
) = Transient thermal resistance, see figure 11)
D (ave)
1.0E-01
= 1/2 ( 1.3·BV·I
I
E
Allowed avalanche Current vs
avalanche
assuming
avalanche losses
av
AS (AR)
= 2DT/ [1.3·BV·Z
= P
D (ave)
jmax
pulsewidth,
Tj = 25°C due to
av
av
. This is validated for
·f
1.0E+00
) = DT/ Z
·t
th
av
]
thJC
tav
jmax
1.0E+01
7
is