HA5024IPZ Intersil, HA5024IPZ Datasheet - Page 10

IC AMP VIDEO 125MHZ QUAD 20-PDIP

HA5024IPZ

Manufacturer Part Number
HA5024IPZ
Description
IC AMP VIDEO 125MHZ QUAD 20-PDIP
Manufacturer
Intersil
Datasheets

Specifications of HA5024IPZ

Applications
Current Feedback
Number Of Circuits
4
-3db Bandwidth
125MHz
Slew Rate
350 V/µs
Current - Supply
7.5mA
Current - Output / Channel
20mA
Voltage - Supply, Single/dual (±)
±4.5 V ~ 18 V
Mounting Type
Through Hole
Package / Case
20-DIP (0.300", 7.62mm)
Amplifier Type
High Slew Rate, High Speed, Video
Bandwidth
125 MHz
Common Mode Rejection Ratio
50
Current, Input Bias
4 μA
Current, Output
20 mA
Current, Supply
7.5 mA
Number Of Amplifiers
Quad
Package Type
PDIP-20
Temperature, Operating, Range
-40 to +85 °C
Time, Fall
6 ns
Time, Rise
6 ns
Voltage, Gain
65 dB
Voltage, Input
±5 V
Voltage, Noise
4.5 nV/sqrt Hz
Voltage, Offset
5 mV
Voltage, Output, High
+3 V
Voltage, Output, Low
-3 V
Voltage, Supply
36 V
Lead Free Status / RoHS Status
Lead free / RoHS Compliant

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
HA5024IPZ
Manufacturer:
Intersil
Quantity:
234
Typical Performance Curves
FIGURE 13. PHASE RESPONSE AS A FUNCTION OF
FIGURE 15. BANDWIDTH AND GAIN PEAKING vs FEEDBACK
100
-1
-2
-3
-4
-5
-135
-100
-225
-270
-315
-360
95
90
5
4
3
2
1
0
FIGURE 11. NON-INVERTING FREQUENCY RESPONSE
-45
-90
350
2
0
2
V
C
V
C
A
OUT
L
OUT
L
V
= 10pF
= 10pF
= -1, R
FREQUENCY
RESISTANCE
= 0.2V
GAIN PEAKING
500
= 0.2V
F
A
P-P
= 750Ω
P-P
FEEDBACK RESISTOR (Ω)
V
= +10, R
-3dB BANDWIDTH
FREQUENCY (MHz)
FREQUENCY (MHz)
10
10
650
A
A
V
A
V
V
= 10, R
= 2, R
A
= 5, R
F
10
V
= 383Ω
= -10, R
F
F
800
F
= 681Ω
= 383Ω
= 1kΩ
A
F
V
= 750Ω
V
C
A
= +1, R
OUT
L
V
= 10pF
= +2
950
A
= 0.2V
V
Unless Otherwise Specified
V
100
SUPPLY
F
= +1, R
= 1kΩ
P-P
100
F
200
1100
= ±5V, A
= 1kΩ
180
135
90
45
0
-45
-90
-135
-180
10
5
0
200
HA5024
V
= +1, R
F
FIGURE 14. BANDWIDTH AND GAIN PEAKING vs FEEDBACK
FIGURE 16. BANDWIDTH AND GAIN PEAKING vs LOAD
= 1kΩ, R
-1
-2
-3
-4
-5
5
4
3
2
1
0
140
130
120
2
130
120
100
500
110
FIGURE 12. INVERTING FREQUENCY RESPONSE
90
80
0
L
-3dB BANDWIDTH
V
C
R
GAIN PEAKING
= 400Ω, T
OUT
L
F
A
= 10pF
RESISTANCE
RESISTANCE
= 750Ω
V
= 0.2V
= -10
700
200
P-P
FEEDBACK RESISTOR (Ω)
A
= 25°C,
A
LOAD RESISTOR (Ω)
V
10
FREQUENCY (MHz)
900
= -5
400
-3dB BANDWIDTH
1100
600
V
C
A
OUT
V
L
V
GAIN PEAKING
OUT
C
A
= 10pF
= +1
1300
L
V
= 0.2V
= 10pF
= +1
800
= 0.2V
February 8, 2006
P-P
100
P-P
1500
A
A
V
V
1000
10
5
0
= -2
= -1
3550.6
6
4
2
0
200

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