2SA2088 Rohm, 2SA2088 Datasheet - Page 2

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2SA2088

Manufacturer Part Number
2SA2088
Description
Medium power transistor ( 60V/0.5A)
Manufacturer
Rohm
Datasheet

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Manufacturer:
ROHM
Quantity:
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Transistors
! ! ! ! Electrical characteristics (Ta=25°C)
! ! ! ! h
! ! ! ! Electrical characteristic curves
∗1 Non repetitive pulse
∗2 See Switching charactaristics measurement circuits
Collector-emitter breakdown voltage
Collector-base breakdown voltage
Emitter-base breakdown voltage
Collector cut-off current
Emitter cut-off current
Collector-emitter saturation voltage
DC current gain
Transition frequency
Corrector output capacitance
Turn-on time
Storage time
Fall time
−0.001
1000
−0.01
100
−0.1
−10
FE
10
−1
−0.001
−0.1
COLLECTOR TO EMITTER VOLTAGE : V
120−270
RANK
Single
non repetitive
Pulsed
Fig.4 DC Current Gain vs.
Fig.1 Safe Operating Area
COLLECTOR CURRENT : I
Q
Parameter
Collector Current
−0.01
−1
DC
V
V
V
100ms
10ms
1ms
CE
CE
CE
= −5V
= −3V
= −2V
−0.1
−10
Ta=25°C
C
(ΙΙ)
(A)
500µs
CE
−100
−1
(V)
Symbol
V
BV
BV
BV
Tstg
I
I
CE (sat)
Ton
h
C
CBO
EBO
Tf
f
FE
CEO
CBO
T
EBO
ob
−0.01
−0.1
1000
−10
Fig.5 Collector-Emitter Saturation
100
−1
−0.001
10
−60
−60
120
Min.
−6
−0.01
Voltage vs. Collector Current
COLLECTOR CURRENT : I
COLLECTOR CURRENT : I
Fig.2 Switching Time
Ta=125°C
Ta=25°C
Ta= −40°C
−150
Typ.
400
110
−0.01
10
40
60
Tstg
Ton
Tf
−0.1
−300
−1.0
−1.0
Max.
270
−0.1
I
C
Ta=25°C
V
I
C
/ I
CC
/ I
B
C
= −25V
B
=10 / 1
C
=10 / 1
(A)
(A)
MHz
Unit
mV
µA
µA
pF
ns
ns
ns
V
V
V
(Ι)
−1
−1
I
I
I
V
V
I
I
V
I
V
I
f=10MHz
V
I
f=1MHz
I
I
I
V
C
C
E
C
B
C
E
E
C
B1
B2
CB
EB
CE
CE
CB
CC
= −1mA
= −100µA
= −100µA
= −100mA
= −10mA
= −50mA
=100mA
=0A
= −500mA
= −50mA
=50mA
= −4V
= −40V
= −2V
= −10V
= −10V
−25V
−0.01
1000
−0.1
Condition
−10
100
Fig.6 Collector-Emitter Saturation
−1
−0.001
10
−0.001
Ta=125°C
Ta=25°C
Ta= −40°C
Voltage vs. Collector Current
Fig.3 DC Current Gain vs.
COLLECTOR CURRENT : I
COLLECTOR CURRENT : I
I
I
I
C
C
C
/ I
/ I
/ I
−0.01
B
B
B
−0.01
Collector Current
=100/1
=20/1
=10/1
∗1
∗2
2SA2088
−0.1
−0.1
Ta=25°C
V
CE
C
C
(A)
= −2V
(Ι)
(A)
2/3
(ΙΙ)
−1
−1

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