ADE7759 Analog Devices, ADE7759 Datasheet - Page 20

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ADE7759

Manufacturer Part Number
ADE7759
Description
Active Energy Metering IC with di/dt Sensor Interface
Manufacturer
Analog Devices
Datasheet

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ADE7759
V1
V2
V1N
V2N
V1P
V2P
V1
–0.05
–0.10
–0.05
–0.10
0.30
0.25
0.20
0.15
0.10
0.05
0.00
PGA1
PGA2
0.30
0.25
0.20
0.15
0.10
0.05
0.00
V2
40
60Hz
100
ADC 2
0.1
ADC 1
45
200
300
1
50
7
FREQUENCY – Hz
400
FREQUENCY – Hz
1
–110 s TO +103 s
DELAY BLOCK
1
1.12 s/LSB
PHCAL [7:0]
1
500
55
1
HPF
1
600
1
0
60
20
700
0
0
800
CHANNEL 2 DELAY
REDUCED BY 4.48 s
(0.1 LEAD AT 60Hz)
FCH IN PHCAL [7:0]
V2
65
20
V1
60Hz
900
LPF2
1000
70
ACTIVE POWER CALCULATION
Electrical power is defined as the rate of energy flow from
source to load. It is given by the product of the voltage and current
waveforms. The resulting waveform is called the instantaneous
power signal, and it is equal to the rate of energy flow at every
instant of time. The unit of power is the watt or joules/second
Equation 3 gives an expression for the instantaneous power signal
in an ac system.
where
The average power over an integral number of line cycles (n) is
given by the expression in Equation 4.
where T is the line cycle period. P is referred to as the Active or
Real Power. Note that the active power is equal to the dc com-
ponent of the instantaneous power signal p(t) in Equation 3, i.e.,
VI. This is the relationship used to calculate active power in the
ADE7759. The instantaneous power signal p(t) is generated by
multiplying the current and voltage signals. The dc component of
the instantaneous power signal is then extracted by LPF2
(Low-Pass Filter) to obtain the active power information. This
process is illustrated graphically in Figure 32. Since LPF2 does not
have an ideal “brick wall” frequency response (see Figure 33),
the Active Power signal will have some ripple due to the instanta-
neous power signal. This ripple is sinusoidal and has a frequency
equal to twice the line frequency. Since the ripple is sinusoidal
in nature it will be removed when the Active Power signal is
integrated to calculate Energy—see Energy Calculation section.
V = rms voltage,
I = rms current.
v t
i t
P
p t
p t
( )
( )
( )
( )
=
= 2
= 2
nT
=
=
–0.1
–0.2
–0.3
–0.4
1
0.4
0.3
0.2
0.1
0.0
VI VI
v t
( )
54
nT
0
I
V
p t dt VI
×
sin(
(
( )
ω
i t
( )
cos(
t
)
ω
56
t
)
=
t
)
58
FREQUENCY – Hz
60
62
64
66
(1)
(2)
(3)
(4)

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