HCPL-316 ETC, HCPL-316 Datasheet - Page 29

• Manufacturer Part Number: HCPL-316
• Description: 2.0 Amp Gate Drive Optocoupler with Integrated (VCE) Desaturation Detection and Fault Status Feedback
• Manufacturer: ETC

3. Compare the input and output
As an example, the total input
and output power dissipation can
be calculated given the following
conditions:
Step 1: Calculate R
from I
To find the peak charging l
assume that the gate is initially
charged the steady-state value of
V
following relationship:
R
(Note from Figure 76 that the
real value of I
the value calculated from the
simple model shown.)
Step 2: Calculate total power
dissipation in the HCPL-316J:
EE
G
= 10.25
[V
= [V
18 V – 1 V – (1.5 V + (-5 V))
(Average switching energy
supplied to HCPL-316J per
cycle vs. R
power dissipation calculated in
step #2 to the maximum
recommended dissipation for
the HCPL-316J. (If the
maximum recommended level
has been exceeded, it may be
necessary to raise the value of
R
power and repeat step #2.)
• I
• V
• V
• f
=
. Therefore apply the
G
OH
10.5
to lower the switching
ON, MAX
CARRIER
CC2
EE
OL
CC2
@650 A – (V
= -5 V
peak specification:
= 18 V
– 1 – (V
(for a 1% resistor)
I
I
OL,PEAK
OL,PEAK
OL
G
~ 2.0 A
= 15 kHz
2.0 A
plot);
may vary from
OL
G
OL
+ V
minimum
+V
EE
OL
EE
)]
)]
The HCPL-316J total power
dissipation (P
sum of the input-side power (P
and output-side power (P
For R
from Figure 77 is E
6.05 J. Assume a worst-case
average I
given by the average of I
I
I
P
P
Step 3: Compare the
calculated power dissipation
with the absolute maximum
values for the HCPL-316J:
For the example,
where,
P
dissipation in the HCPL-316J
due to biasing the device.
P
dissipation in the HCPL-316J
due to charging and discharging
power device gate.
E
dissipated in HCPL-316J due to
switching of the power device
over one switching cycle
( J/cycle).
f
frequency.
CC1L
CC2
SWITCH
I
O
O(BIAS)
O(SWITCH)
SWITCH
= 16.5 mA * 5.5 V = 90.8 mW
= P
= 5.5 mA * (18 V – (–5 V)) +
= 126.5 mW + 90.8 mW
= 217.3 mW
P
P
P
T
I
O
= 5.5 mA.
G
). Similarly the average
= P
= I
= P
= I
O(BIAS)
= 10.5, the value read
6.051 J * 15 kHz
= average carrier signal
CC1
= steady-state power
= Average Energy
CC1
CC2
I
O(BIAS)
E
+ P
SWITCH
= transient power
= 16.5 mA (which is
T
* V
* (V
+ P
) is equal to the
O
CC1
+ P
CC2
O,SWITCH
SWITCH
* f
–V
O,SWTICH
SWITCH
EE
CC1H
O
):
=
) +
and
I
)
Figure 76. Typical Peak I
Currents vs. Rg (for HCPL-316J
Output Driving an IGBT Rated at
600 V/100 A.
29
Figure 77. Switching Energy Plot for
Calculating Average Pswitch (for
HCPL-316J Output Driving an IGBT
Rated at 600 V/100 A).
Therefore, the power dissipation
absolute maximum rating has not
been exceeded for the example.
Please refer to the following
Thermal Model section for an
explanation on how to calculate
the maximum junction
temperature of the HCPL-316J
for a given PC board layout
configuration.
P
P
-1
-2
-3
SWITCHING ENERGY vs. GATE RESISTANCE
4
3
2
1
0
I
O
9
8
7
6
5
4
3
2
1
0
MAX. I
0
0
= 90.8 mW < 150 mW
= 217.3 mW < 400 mW
20
(abs. max.)
(abs. max.)
ON
40 60 80
(V
(V
, I
CC2
50
CC2
OFF
Ess (Qg = 650 nC)
/ V
I
I
OFF
ON
/ V
vs. GATE RESISTANCE
Rg ( )
EE2
Rg ( )
100
EE2
(MAX.)
100
(MAX.)
= 25 V / 5 V
120
= 25 V / 5 V
ON
140
OK
OK
150
and I
160 180
OFF
200
200