IDT89HPES24N3A1ZCBXG IDT, Integrated Device Technology Inc, IDT89HPES24N3A1ZCBXG Datasheet - Page 14
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IDT89HPES24N3A1ZCBXG
Manufacturer Part Number
IDT89HPES24N3A1ZCBXG
Description
IC PCI SW 24LANE 3PORT 420-SBGA
Manufacturer
IDT, Integrated Device Technology Inc
Datasheet
1.IDT89HPES24N3A1ZCBX8.pdf
(31 pages)
Specifications of IDT89HPES24N3A1ZCBXG
Lead Free Status / RoHS Status
Lead free / RoHS Compliant
Other names
89HPES24N3A1ZCBXG
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
IDT89HPES24N3A1ZCBXG
Manufacturer:
IDT, Integrated Device Technology Inc
Quantity:
10 000
Company:
Part Number:
IDT89HPES24N3A1ZCBXG8
Manufacturer:
IDT, Integrated Device Technology Inc
Quantity:
10 000
Heat Sink
in most cases.
Thermal Usage Examples
heat sink. The general formula to determine
maximum T
this scenario. The formula is also useful from a system design perspective. It can be used to determine if a heat sink should be added to the device
based on some desired value of T
ssdhelp@idt.com for further assistance.
IDT 89HPES24N3A Data Sheet
Table 17 lists heat sink requirements for the PES24N3A under three common usage scenarios. As shown in this table, a heat sink is not required
.
The junction-to-ambient thermal resistance is a measure of a device’s ability to dissipate heat from the die to its surroundings in the absence of a
Thermal reliability of a device is generally assured when the actual value of T
The actual T
An appropriate level of increased air flow and/or a heat sink can be added to achieve this lower ambient temperature. Please contact
1 m/S or more
Air Flow
J
T
T
θ
T
Zero
Zero
specified for the device. Using an ambient temperature of 70
A(allowed)
A(allowed)
J(actual)
JA
J
= (T
of 103
J
= T
- T
= T
= 100
o
A
A
C is well below the maximum T
J(desired)
)/P
+ P *
o
C - (3.9W * 8.5W/
θ
3.9”x6.2” (ExpressModule form factor) or larger
JA(eff)
J
- (P *
. For example, if for reliability purposes the desired T
Table 17 Heat Sink Requirements Based on Air Flow and Board Characteristics
= 70
θ
JA(effective)
o
θ
C + 3.9W * 8.5W/
JA
o
Board Size
C) = 100
is:
)
Any
Any
J
o
C - 33
of 125
o
C = 103
o
o
C = 67
C specified for the device (shown in Table 16). Therefore, no heat sink is needed in
14 of 31
o
o
C
C
o
C and assuming a system with 1m/S airflow, the actual value of T
J
in the specific system environment being considered is less than the
Board Layers
J
is 100
10 or more
14 or more
Any
o
C, then the maximum allowable T
Heat Sink Requirement
No heat sink required
No heat sink required
No heat sink required
A
April 23, 2008
is:
J
is: