JC050C1 Lineage Power, JC050C1 Datasheet - Page 13

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JC050C1

Manufacturer Part Number
JC050C1
Description
CONVERTER DC/DC 15V 50W OUT
Manufacturer
Lineage Power
Series
JC050r
Type
Isolated with Remote On/Offr
Datasheet

Specifications of JC050C1

Output
15V
Number Of Outputs
1
Power (watts)
50W
Mounting Type
Through Hole
Voltage - Input
18 ~ 36V
Package / Case
9-DIP Module
1st Output
15 VDC @ 3.33A
Size / Dimension
2.40" L x 2.28" W x 0.50" H (61mm x 57.9mm x 12.7mm)
Power (watts) - Rated
50W
Operating Temperature
-40°C ~ 100°C
Efficiency
88%
Approvals
CSA, UL, VDE
Product
Isolated
Output Power
50 W
Input Voltage Range
18 V to 36 V
Input Voltage (nominal)
28 V
Output Voltage (channel 1)
15 V
Output Current (channel 1)
3.33 A
Isolation Voltage
1.5 KV
Package / Case Size
DIP
Output Type
Isolated
Output Voltage
15 V
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
3rd Output
-
2nd Output
-
4th Output
-
Lead Free Status / Rohs Status
Lead free / RoHS Compliant

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
JC050C1
Manufacturer:
LUCENT
Quantity:
1 000
Part Number:
JC050C1
Quantity:
55
Thermal considerations
Heat Transfer with Heat Sinks
Solution
Given: V
Determine P
Then solve the following equation:
Use Figure 24 to determine air velocity for the0.5 inch
heat sink.
The minimum airflow necessary for the JC100C
module is 1.0 m/s (200 ft./min.).
θ
θ
θ
ca
ca
ca
Data Sheet
March 2008
I
T
T
Heat sink = 0.5 in.
P
Lineage Power
O
=
=
=
A
C
I
D
= 28 V
= 6 A
= 40 °C
= 85 °C
= 14.0 W
3.2
D
(
----------------------- -
(
----------------------- -
T
85 40
by using Figure 23:
°C/W
C
14.0
P
D
T
A
)
)
(continued)
(continued)
JC050C, JC075C, JC100C Power Modules: dc-dc Converters;
18 Vdc to 36 Vdc Input, 15 Vdc Output; 50 W to 100 W
Custom Heat Sinks
A more detailed model can be used to determine the
required thermal resistance of a heat sink to provide
necessary cooling. The total module resistance can be
separated into a resistance from case-to-sink (θcs) and
sink-to-ambient (θsa) shown below (Figure 25).
Figure 25. Resistance from Case-to-Sink and
For a managed interface using thermal grease or foils,
a value of θcs = 0.1 °C/W to 0.3 °C/W is typical. The
solution for heat sink resistance is:
This equation assumes that all dissipated power must
be shed by the heat sink. Depending on the user-
defined application environment, a more accurate
model, including heat transfer from the sides and bot-
tom of the module, can be used. This equation pro-
vides a conservative estimate for such instances.
Layout Considerations
Copper paths must not be routed beneath the power
module mounting inserts.
θ
sa
P
=
D
(
------------------------ -
Sink-to-Ambient
T
C
P
T
D
C
T
A
)
θcs
θ
cs
T
S
θsa
T
A
8-1304
13

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