BZ015A104ZAB AVX Corporation, BZ015A104ZAB Datasheet - Page 21

• Manufacturer Part Number: BZ015A104ZAB
• Description: Capacitor,Non-Specified,100mF,5.5VDC,20-% Tol,80+% Tol
• Manufacturer: AVX Corporation
• Series: BZr

Specifications of BZ015A104ZAB

• Capacitance: 0.1 Farad
• Tolerance: - 20 %, 80 %
• Voltage Rating: 5.5 Volts
• Esr: 80 mOhms
• Operating Temperature Range: - 20 C to + 70 C
• Dimensions: 17 mm W x 28 mm L x 2.1 mm H
• Leakage Current: 10 uAmps
• Load Life: 1000 Hrs
• Product: Super Capacitors
• Lead Free Status / Rohs Status: Lead free / RoHS Compliant

BestCap
High Power Pulse Supercapacitors
20
3.5
2.5
3.5
2.5
4
3
2
4
3
2
0
0
GSM Pulse @ 2 Amps
Figure 6a. Li-ION Battery at +25°C
Figure 6b. Li-ION Battery at +0°C
Battery with Pulse Capacitor
Battery with Pulse Capacitor
100
100
Cutoff Voltage
3.4 Volts
3.5 Volts
3.6 Volts
Cutoff Voltage
3.4 Volts
3.5 Volts
3.6 Volts
®
200
Time (Minutes)
Ultra-low ESR
Time (Minutes)
200
GSM Pulse @ 2 Amps 0°C
% Increase
28%
100%
300%
% Increase
28%
73%
300%
300
Cutoff Voltage Limits
300
Battery Alone
Battery Alone
LI-ION Battery
400
500
400
PULSE CAPACITOR APPLICATIONS
As mentioned earlier, the voltage drop in a circuit is critical
as the circuit will not operate below a certain cut-off voltage.
There are two sources of voltage drop (ΔV) which occur, the
first ΔV
(ESR) and the second, called the capacitive drop, is ΔV
From Ohm’s law,
Let us say that the instantaneous starting voltage is Vo, or
voltage for the circuit from where the voltage drops. If the
capacitor has an ESR of 100 milliOhms and the current is 1
amp,
On demand, during the discharge mode, the voltage V = Vo
- ΔV
The second voltage drop is because of the capacitance.
This is shown in the equation as a linear function because of
simplicity. Simply put,
Hence, ΔV
I x dt/C. This formula states that the larger the capacitance
value the lower the voltage drop. Compared to a Ta capacitor
this ΔV
BestCap
needed. If the current pulse itself is 1 amp, the current pulse
width is 1 second, and the capacitance is 10 millifarads, the
ΔV
is out of the range of BestCap
becomes narrower, say 10 milli-seconds, and the capaci-
tance is 100 millifarads, the ΔV
= 0.1 volt or 100 milli-volts. This shows the advantage of the
large capacitance and hence the term “pulse” capacitor.
The specific power – specific energy graphs are used in the
battery industry to compare competitive products. As the dt
becomes smaller i.e.100 milliseconds, 10 milliseconds and
then 1 millisecond, our estimates show that the specific
power for the BestCap
competitors because of our choice of internal materials
chemistry.
Conclusion: we now clearly show that BestCap
advantage over competitors for short current pulse whose
widths are smaller than a few hundred milliseconds.
ΔV
C
The derivative, dQ/dt = I (current, in amps) = C x dV/dt
ESR
ESR
= 1A x 1Sec/0.01F, or a 100 volts; such an application
= 1 amp x (0.100) ohms = 0.1 volts or 100 milli-volts.
ESR
C
= (Vo - 0.1) volts
®
Q (charge) = C (capacitance) x V (voltage)
is reduced by a factor of about 10 to 100. So,
is because of the equivalent series resistance
C
voltage = current x resistance or V = IR
has an advantage where higher capacitance is
(dV, the voltage drop because of capacitance) =
®
is the highest as compared to our
®
C
. However, if the pulse width
= 1 x (10/1000)/(100/1000)
®
has an
C
.