mt89l86apr1 Zarlink Semiconductor, mt89l86apr1 Datasheet - Page 11

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mt89l86apr1

Manufacturer Part Number
mt89l86apr1
Description
512 X 256 Channels 3.3 V Multiple Rate Digital Switch Mrdx With Constant Delay Mode
Manufacturer
Zarlink Semiconductor
Datasheet

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n= input channel, t.s. = time-slot
Notes: dmin and dmax are measured in time-slots and at the point in time when the output channel is completely shifted out.
Constant Throughput Delay mode (V/C bit = 1)
In this mode frame sequence integrity is maintained in both Identical and Different I/O Data Rate operations by
making use of a multiple Data-Memory buffer technique. The input channels written in any of the buffers during
frame N will be read out during frame N+2. In applications at 2.048 Mb/s for instance, the minimum throughput
delay achievable in constant delay mode will be 32 time-slots; for example, when input time-slot 32 (channel 31) is
switched to output time-slot 1 (channel 0). Likewise, the maximum delay is achieved when the first time slot in a
frame (channel 0) is switched to the last time-slot in the frame (channel 31), resulting in 94 time-slots of delay.
To summarize, any input time-slot from input frame N will always be switched to the destination time-slot on output frame
N+2. Table 4 describes the constant throughput delay values at different data rates.
2 Mb/s to 4 Mb/s
2 Mb/s to 8 Mb/s
4 Mb/s to 2 Mb/s
8 Mb/s to 2 Mb/s
t.s. = time-slot
fr. = 125 µs frame
2 Mb/s t.s. = 3.9 µs
4 Mb/s t.s. = 1.95 µs
8 Mb/s t.s. = 0.975 µs
Configuration
I/O Data Rate
Table 3b - Min/Max Throughput Delay Values for Different I/O Rate Applications
dmin=5x 4Mb/s t.s.
dmax=1 fr.+(4x 4Mb/s t.s.)
dmin=9x 8Mb/s t.s.
dmax=1 fr.+(8x 8Mb/s t.s.)
dmin=3x 2Mb/s t.s.
dmax=1 fr.+(2x 2Mb/s t.s.)
dmin=3x 2Mb/s t.s.
dmax=1 fr.+(2x 2Mb/s
0, 1
t.s.)
dmin=(2x 2Mb/s t.s.)+
dmax=1 fr.+(1x 2Mb/s
Zarlink Semiconductor Inc.
(3x 8Mb/s t.s.)
t.s.)+(3x 8Mb/s t.s.)
MT89L86
2, 3
11
Output Stream Used
dmin=(2x 2Mb/s t.s.)+(1x 4Mb/s t.s.)
dmax=1 fr.+(1x 2Mb/s t.s.)+(1x 4Mb/s t.s.)
dmin=(2x 2Mb/s t.s.)+
dmax=1 fr.+(1x 2Mb/s
(2x 8Mb/s t.s.)
t.s.)+(2x 8Mb/s t.s.)
4, 5
dmin=(2x 2Mb/s t.s.)+
dmax=1 fr.+(1x 2Mb/s
(1x 8Mb/s t.s.)
t.s.)+(1x 8Mb/s t.s.)
Data Sheet
6, 7

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