C40K-CDR-A Omron, C40K-CDR-A Datasheet - Page 153

• Manufacturer Part Number: C40K-CDR-A
• Description: PROGRAMMABLE CONTROLLER CPU
• Manufacturer: Omron

Specifications of C40K-CDR-A

• Leaded Process Compatible: No
• Peak Reflow Compatible (260 C): No
• Lead Free Status / RoHS Status: Contains lead / RoHS non-compliant

Calculating Cycle Time
6-3-2
142
Calculations
1.
2.
3.
4.
Total
Overseeing
Input/output refreshing
Peripheral device servicing
Instruction execution
PC with Additional Units
Process
The cycle time is the total of all these calculations.
1.6 ms + 0.51 ms + 4.43 ms = 6.54 ms
If a peripheral device had been present it would have been:
1.6 ms + 0.51 ms + 4.43 ms + 1 ms = 7.54 ms
Configuration: A C40K CPU, a C40P Expansion I/O Unit, an I/O Link Unit.
Program: 1150 addresses.
Average instruction execution time: 30 s.
The equation for the cycle time from above is as follows:
Cycle time = Overseeing time
The overseeing time is fixed at 1.6 ms.
The input/output refresh time would be as follows: 0.51 ms + (0.03 ms x N ).
As the C40K is provided with only one input and one output word and the
C40P Expansion unit contains input and output words the value of the con-
stant N is 8. (i.e., N = 10 – 2 = 8) and so the time required is 0.51 ms + (0.03
ms x 8) = 0.75 ms.
The total execution time can be calculated by obtaining the average instruc-
tion execution time and multiplying this by the number of addresses used in
the program. As given above the average instruction execution time is 30 s.
Total execution time = 1150 addresses x 30 s = 34.50 ms
The peripheral device servicing time is calculated by adding the other three
time values and multiplying the result by a factor of 0.05. This value is only
required in configurations where a peripheral device is connected to the PC.
The result is calculated as an example. As there are no peripheral devices
used in this example the following results will be ignored in the final calcula-
tion.
Peripheral device servicing = (1.6 ms + 0.75 ms + 34.50 ms) x 0.05 =
1.84 ms which is rounded down to 1.50 ms.
Fixed
0.29 + 0.07 * (1–1)
((1) + (3) + (4)) * 0.05 = 0.3 < 1
14.75 * 300
(1) + (2) + (3) + (4)
+ Input/output refreshing
+ Peripheral device servicing time
+ Instruction execution time
Formula
1.6
0.51
1.00
4.43
7.54
Peripheral device servicing (ms)
With
1.6
0.51
0.00
4.43
6.54
Section 6-3
Without