AT89C51CC01 Atmel Corporation, AT89C51CC01 Datasheet - Page 105
AT89C51CC01
Manufacturer Part Number
AT89C51CC01
Description
Manufacturer
Atmel Corporation
Datasheets
1.AT89C51CC01.pdf
(167 pages)
2.AT89C51CC01.pdf
(12 pages)
3.AT89C51CC01.pdf
(32 pages)
4.AT89C51CC01.pdf
(29 pages)
Specifications of AT89C51CC01
Flash (kbytes)
32 Kbytes
Max. Operating Frequency
40 MHz
Cpu
8051-12C
Max I/o Pins
34
Uart
1
Can
1
Adc Channels
8
Adc Resolution (bits)
10
Adc Speed (ksps)
62.5
Sram (kbytes)
1.25
Eeprom (bytes)
2048
Self Program Memory
API
Operating Voltage (vcc)
3.0 to 5.5
Timers
4
Isp
UART/CAN
Watchdog
Yes
Available stocks
Company
Part Number
Manufacturer
Quantity
Price
Company:
Part Number:
AT89C51CC01CA-IM
Manufacturer:
ATMEL
Quantity:
831
Company:
Part Number:
AT89C51CC01CA-RLTUM
Manufacturer:
ATMEL
Quantity:
4 000
Company:
Part Number:
AT89C51CC01CA-RLTUM
Manufacturer:
Atmel
Quantity:
3 136
Company:
Part Number:
AT89C51CC01CA-SLIM
Manufacturer:
ATMEL
Quantity:
11
Company:
Part Number:
AT89C51CC01CA-SLSUM
Manufacturer:
ATMEL
Quantity:
2 916
Part Number:
AT89C51CC01UA-RLTUM
Manufacturer:
ATMEL/爱特梅尔
Quantity:
20 000
Part Number:
AT89C51CC01UA-UM
Manufacturer:
ATMEL/爱特梅尔
Quantity:
20 000
4129N–CAN–03/08
Table 72. CANBT3 Register
CANBT3 (S:B6h)
CAN Bit Timing Registers 3
Note:
No default value after reset.
Number
Bit
6-4
3-1
7
-
7
0
The CAN controller bit timing registers must be accessed only if the CAN controller is dis-
abled with the ENA bit of the CANGCON register set to 0.
See Figure 48.
Bit Mnemonic Description
PHS2 2
PHS2 2:0
PHS1 2:0
SMP
6
-
PHS2 1
Reserved
The value read from this bit is indeterminate. Do not set this bit.
Phase Segment 2
This phase is used to compensate for phase edge errors. This segment can
be shortened by the re-synchronization jump width.
Phase segment 2 is the maximum of Phase segment1 and the Information
Processing Time (= 2TQ).
Phase Segment 1
This phase is used to compensate for phase edge errors. This segment can
be lengthened by the re-synchronization jump width.
Sample Type
0 - once, at the sample point.
1 - three times, the threefold sampling of the bus is the sample point and twice
over a distance of a 1/2 period of the Tscl. The result corresponds to the
majority decision of the three values.
5
PHS2 0
4
Tphs2 = Tscl x (PHS2[2..0] + 1)
Tphs1 = Tscl x (PHS1[2..0] + 1)
PHS1 2
3
PHS1 1
2
PHS1 0
1
SMP
0
105