DF2148BTE20 Renesas Electronics America, DF2148BTE20 Datasheet - Page 761

IC H8S MCU FLASH 128K 100-QFP

DF2148BTE20

Manufacturer Part Number
DF2148BTE20
Description
IC H8S MCU FLASH 128K 100-QFP
Manufacturer
Renesas Electronics America
Series
H8® H8S/2100r
Datasheets

Specifications of DF2148BTE20

Core Processor
H8S/2000
Core Size
16-Bit
Speed
20MHz
Connectivity
I²C, IrDA, SCI, X-Bus
Peripherals
PWM, WDT
Number Of I /o
74
Program Memory Size
128KB (128K x 8)
Program Memory Type
FLASH
Ram Size
4K x 8
Voltage - Supply (vcc/vdd)
4.5 V ~ 5.5 V
Data Converters
A/D 8x10b; D/A 2x8b
Oscillator Type
Internal
Operating Temperature
-20°C ~ 75°C
Package / Case
100-TQFP, 100-VQFP
Lead Free Status / RoHS Status
Contains lead / RoHS non-compliant
Eeprom Size
-
Other names
HD64F2148BTE20
HD64F2148BTE20

Available stocks

Company
Part Number
Manufacturer
Quantity
Price
Part Number:
DF2148BTE20V
Manufacturer:
Renesas Electronics America
Quantity:
10 000
Table 27.2 DC Characteristics (2)
Conditions: V
Input
leakage
current
Three-state
leakage
current (off
state)
Input
pull-up
MOS
current
Input
capacitance
AV
RES
STBY, NMI, MD1,
MD0
Port 7
Ports 1 to 6, 8, 9, A *
and B (Ports C to G
are added in the
H8S/2160B and
H8S/2161B.)
Ports 1 to 3
Ports 6 (P6PUE = 0)
and B
(Ports C to F are
added in the
H8S/2160B and
H8S/2161B.)
Ports A *
Port 6 (P6PUE = 1)
RES
NMI
P52, P97, P42,
P86, PA7 to PA2
Input pins except (4)
above
(Ports C to G are
added in the
H8S/2160B and
H8S/2161B.)
CC
Item
ref
= 2.7 V to 3.6 V *
*
1
= 2.7 V to AV
4
(4)
4
,
5
CC
, V
, V
Symbol Min
–I
C
CC
I
I
in
P
in
TSI
SS
B = 2.7 V to 5.5 V, AV
= AV
SS
5
30
30
3
*
1
= 0 V, T
Rev. 3.00 Mar 21, 2006 page 705 of 788
Typ
a
= –20 to +75°C
Section 27 Electrical Characteristics
CC
*
1
Max
10.0
1.0
1.0
1.0
150
300
600
100
80
50
20
15
= 2.7 V to 3.6 V,
Unit
µA
µA
µA
pF
pF
pF
pF
REJ09B0300-0300
Test
Conditions
V
V
V
AV
V
V
V
V
V
V
to 3.6 V
V
to 5.5 V
V
f = 1 MHz,
T
a
in
CC
in
in
CC
in
CC
in
CC
CC
in
= 25°C
= 0.5 to
= 0.5 to
CC
= 0.5 to
= 0.5 to
= 0 V,
= 0 V,
B – 0.5 V
B = 2.7 V
– 0.5 V
– 0.5 V,
= 2.7 V
– 0.5 V

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